Java 用最小值定义频带

我正在使用一个Minim BeatDetect对象来分析传入的麦克风信号。BeatDetect使用FFT

在BeatDetect类中，有四个感兴趣的函数：

isHat（）

、

isKick（）

、

isSnare（）

和

isRange（int，int，int）

。前三个是

isRange（）

的自定义版本。我试着做的是识别不仅仅是帽子、踢腿和圈套鼓

为了做到这一点，我需要理解方法

isHat（）

、

isKick（）

和

isSnare（）

中的数学知识。我希望这里有人能帮我。下面是4个函数的代码

/**
 * In frequency energy mode this returns true if a beat corresponding to the
 * frequency range of a kick drum has been detected. This has been tuned to
 * work well with dance / techno music and may not perform well with other
 * styles of music. In sound energy mode this always returns false.
 * 
 * @return boolean: true if a kick drum beat has been detected
 * 
 * @example Analysis/FrequencyEnergyBeatDetection
 * 
 * @related BeatDetect
 */
public boolean isKick()
{
    if (algorithm == SOUND_ENERGY)
    {
        return false;
    }
    int upper = 6 >= spect.avgSize() ? spect.avgSize() : 6;
    return isRange(1, upper, 2);
}

/**
 * In frequency energy mode this returns true if a beat corresponding to the
 * frequency range of a snare drum has been detected. This has been tuned to
 * work well with dance / techno music and may not perform well with other
 * styles of music. In sound energy mode this always returns false.
 * 
 * @return boolean: true if a snare drum beat has been detected
 * 
 * @example Analysis/FrequencyEnergyBeatDetection
 * 
 * @related BeatDetect
 */
public boolean isSnare()
{
    if (algorithm == SOUND_ENERGY)
    {
        return false;
    }
    int lower = 8 >= spect.avgSize() ? spect.avgSize() : 8;
    int upper = spect.avgSize() - 1;
    int thresh = (upper - lower) / 3 + 1;
    return isRange(lower, upper, thresh);
}

/**
 * In frequency energy mode this returns true if a beat corresponding to the
 * frequency range of a hi hat has been detected. This has been tuned to work
 * well with dance / techno music and may not perform well with other styles
 * of music. In sound energy mode this always returns false.
 * 
 * @return boolean: true if a hi hat beat has been detected
 * 
 * @example Analysis/FrequencyEnergyBeatDetection
 * 
 * @related BeatDetect
 */
public boolean isHat()
{
    if (algorithm == SOUND_ENERGY)
    {
        return false;
    }
    int lower = spect.avgSize() - 7 < 0 ? 0 : spect.avgSize() - 7;
    int upper = spect.avgSize() - 1;
    return isRange(lower, upper, 1);
}

/**
 * In frequency energy mode this returns true if at least
 * <code>threshold</code> bands of the bands included in the range
 * <code>[low, high]</code> have registered a beat. In sound energy mode
 * this always returns false.
 * 
 * @param low
 *           int: the index of the lower band
 * @param high
 *           int: the index of the higher band
 * @param threshold
 *           int: the smallest number of bands in the range
 *           <code>[low, high]</code> that need to have registered a beat
 *           for this to return true
 * @return boolean: true if at least <code>threshold</code> bands of the bands
 *         included in the range <code>[low, high]</code> have registered a
 *         beat
 *         
 * @related BeatDetect
 */
public boolean isRange(int low, int high, int threshold)
{
    if (algorithm == SOUND_ENERGY)
    {
        return false;
    }
    int num = 0;
    for (int i = low; i < high + 1; i++)
    {
        if (isOnset(i))
        {
            num++;
        }
    }
    return num >= threshold;
}

我希望通过操纵上述方法，能够准确识别各种乐器的节拍。有人能教我认识到这一点需要什么吗

目前，我了解如果在指定的频带范围内检测到节拍，函数返回

true

。我不明白的是，为什么函数中的参数值[低、高、阈值]与特定仪器相关。谢谢你的意见