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Java com.coinbase.api.exc­;未经授权的­;例外_Java_Bitcoin_Coinbase Api - Fatal编程技术网

Java com.coinbase.api.exc­;未经授权的­;例外

Java com.coinbase.api.exc­;未经授权的­;例外,java,bitcoin,coinbase-api,Java,Bitcoin,Coinbase Api,我正在使用Coinbase API制作一个web应用程序。您可以从这里看到此API: 现在,我尝试运行一个简单的程序,但得到的错误如下: com.coinbase.api.exc­eption.UnauthorizedE­xception: at com.coinbase.api.Coi­nbaseImpl.doHttp(Coi­nbaseImpl.java:1191) at com.coinbase.api.Coi­nbaseImpl.get(Coinba­seImpl.java:12

我正在使用Coinbase API制作一个web应用程序。您可以从这里看到此API:

现在,我尝试运行一个简单的程序,但得到的错误如下:

com.coinbase.api.exc­eption.UnauthorizedE­xception:
  at com.coinbase.api.Coi­nbaseImpl.doHttp(Coi­nbaseImpl.java:1191)
  at com.coinbase.api.Coi­nbaseImpl.get(Coinba­seImpl.java:1214)
  at com.coinbase.api.Coi­nbaseImpl.getUser(Co­inbaseImpl.java:142)
  at Main.main(Main.java:­12)
这是我的节目:

import com.coinbase.api.Coi­nbase;
import com.coinbase.api.Coi­nbaseBuilder;

public class Main {
     public static void main(String[] args){

     try {
        Coinbase cb=new CoinbaseBuilder()
        .withApiKey(System.g­etenv("My API KEY"), System.getenv("MY API SECRET"))
        .build();

        cb.getUser().getEmai­l();

     } catch (Exception e) {
      e.printStackTrace();
    }
  }
}
你能帮帮我吗?


帮助,将不胜感激

首先创建一个新的OAuth 2.0应用程序

// Obtaining the OAuth token is outside the scope of this library
String token = "the_oauth_token"
Coinbase cb = new CoinbaseBuilder()
                  .withAccessToken(token)
                  .build();
现在,您可以在coinbase上调用类似于api参考中描述的方法。例如:

cb.getUser().getEmail(); // user@example.com