Java 不显示android时间选择器对话框的当前时间

我的应用程序中有一个timeIn

editText

。单击时，将弹出时间选择器对话框

    timeIn.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) { //shows timePick
                    isEdited=true;
                    Fragment fragDialog = getSupportFragmentManager().findFragmentByTag("TimePicker");
                    if (fragDialog == null) { // Fragment not added
                        tp.setFlag(TimePick.FLAG_START_DATE);
                        FragmentTransaction ft = getSupportFragmentManager().beginTransaction();
                        tp.show(ft, "TimePicker");
                    } else {

                        // already active
                    }
                }
            });


  public static class TimePick extends android.support.v4.app.DialogFragment implements TimePickerDialog.OnTimeSetListener {

        public static final int FLAG_START_DATE = 00;
        public static final int FLAG_END_DATE = 01;
        private int flag = 00;

        @Override
        public Dialog onCreateDialog(Bundle savedInstanceState) {

            final Calendar c = Calendar.getInstance();
            int hour = c.get(Calendar.HOUR_OF_DAY);
            int minute = c.get(Calendar.MINUTE);
            return new TimePickerDialog(getActivity(), this, hour, minute, DateFormat.is24HourFormat(getActivity()));
        }

        public void setFlag(int i) {
            flag = i;
        }


        @Override
        public void onTimeSet(TimePicker view, int hourofDay, int minute) {

            if (flag == FLAG_START_DATE) {
                timeIn.setText(Integer.toString(hourofDay) + ":" + Integer.toString(minute));
                TimeIn = timeIn.getText().toString();
            }
            if (flag == FLAG_END_DATE) {
                timeOut.setText(Integer.toString(hourofDay) + ":" + Integer.toString(minute));
                TimeOut = timeOut.getText().toString();
            }



        }

    }

---

选择的时间可以是

setText

中的

timeIn

。但是，当我再次单击

editText

中的时间时，

timePicker对话框将弹出当前时间。是否可以使其显示选定的时间而不是当前时间？如果是第一次单击，则仅显示当前时间
 这不是你在这里做的吗

final Calendar c = Calendar.getInstance();
int hour = c.get(Calendar.HOUR_OF_DAY);
int minute = c.get(Calendar.MINUTE);
return new TimePickerDialog(getActivity(), this, hour, minute, DateFormat.is24HourFormat(getActivity()));

您正在将当前时间传递给对话框，这就是它显示当前时间的原因

解决方案：

保存所选时间，并在创建对话框时将其传递给类，并在此代码中使用该时间。如果没有任何选定的时间，则使用当前时间。一点
if-else
阻塞和一些变量就可以了

在外部类中定义这些变量

public static int inHour = -1;
public static int inMin = -1;
public static int outHour = -1;
public static int outMin = -1;

像这样更新
onTimeSet
方法

if (flag == FLAG_START_DATE) {
    inHour = hourofDay;
    inMin = minute;
    timeIn.setText(Integer.toString(hourofDay) + ":" + Integer.toString(minute));
    TimeIn = timeIn.getText().toString();
}
else if (flag == FLAG_END_DATE) {
    outHour = hourofDay;
    outMin = minute;
    timeOut.setText(Integer.toString(hourofDay) + ":" + Integer.toString(minute));
    TimeOut = timeOut.getText().toString();
}

将
onCreateDialog
中的当前代码替换为

final Calendar c = Calendar.getInstance();
int hour = c.get(Calendar.HOUR_OF_DAY);
int min = c.get(Calendar.MINUTE);
if((flag == FLAG_START_DATE) && inHour != -1 && inMin != -1) 
{
     hour = inHour;
     min = inMin;
}
else if((flag == FLAG_END_DATE) && outHour != -1 && outMin != -1) 
{
     hour = outHour;
     min = outMin;
}

return new TimePickerDialog(getActivity(), this, hour, min, DateFormat.is24HourFormat(getActivity()));

保存所选时间，并在创建对话框时将其传递给全班。您能解释更多吗？谢谢谢谢，先生，我稍后会尝试，并告诉您，先生，我在这两行中遇到了错误<代码>小时=小时/天；分钟=分钟

错误：（192,13）错误：非静态变量hour不能从静态上下文中引用

@John Make

hour

和

min

静态lke

公共静态int hour=-1

让我们来看看。