Java Grails将自定义查询检索到映射列表

我是grails的新手

我想为jquery自动完成创建一个控制器

def arrSong = Song.executeQuery("select id, title as value, concat(artist, ' - ', title) as label from ${Song.name} where title like concat('%', :paramTitle, '%')", [paramTitle:params.term?.toString()])
render arrSong as JSON

通过这段代码，我得到了以下JSON：

[[1,"Mr. Brightside","The Killers - Mr. Brightside"]]

我的期望是：

[{"id":1,"value":"Mr. Brightside","label":"The Killers - Mr. Brightside"}]

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任何人都可以提供帮助？

executeQuery

您编写的方式将返回一个未命名结果列表，必须使用索引检索该列表

例如：

[[1,"Mr. Brightside","The Killers - Mr. Brightside"]]

arrSong.each{println it[0]} 
//Prints 1, similarly it[1] for "Mr. Brightside" and so on

您需要的是如下所示的结果集的

映射

表示，然后您应该能够轻松地将映射呈现为JSON

def query = """
             select new map(id as id, 
                            title as value, 
                            concat(artist, ' - ', title) as label) 
             from ${Song.name} 
             where title like concat('%', :paramTitle, '%')
            """

def arrSong = Song.executeQuery(query, [paramTitle: params.term?.toString()])

render arrSong as JSON

应该回来

[{"id":1,"value":"Mr. Brightside","label":"The Killers - Mr. Brightside"}]

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查看AjaxDependencySelection插件。它提供gsp的自动完成功能