RxJava调度程序不';不要睡觉换线
我面临着非常奇怪的RxJava行为,我无法理解 假设我想并行处理元素。我使用flatMap来实现:RxJava调度程序不';不要睡觉换线,java,multithreading,rx-java,Java,Multithreading,Rx Java,我面临着非常奇怪的RxJava行为,我无法理解 假设我想并行处理元素。我使用flatMap来实现: public static void log(String msg) { String threadName = Thread.currentThread().getName(); System.out.println(String.format("%s - %s", threadName, msg)); } public static void sleep(int ms) {
public static void log(String msg) {
String threadName = Thread.currentThread().getName();
System.out.println(String.format("%s - %s", threadName, msg));
}
public static void sleep(int ms) {
try {
Thread.sleep(ms);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public static void main(String[] args) throws InterruptedException {
Scheduler sA = Schedulers.from(Executors.newFixedThreadPool(1));
Scheduler sB = Schedulers.from(Executors.newFixedThreadPool(5));
Observable.create(s -> {
while (true) {
log("start");
s.onNext(Math.random());
sleep(10);
}
}).subscribeOn(sA)
.flatMap(r -> Observable.just(r).subscribeOn(sB))
.doOnNext(r -> log("process"))
.subscribe((r) -> log("finish"));
}
结果是可以预测的:
pool-1-thread-1 - start
pool-2-thread-1 - process
pool-2-thread-1 - finish
pool-1-thread-1 - start
pool-2-thread-2 - process
pool-2-thread-2 - finish
pool-1-thread-1 - start
pool-2-thread-3 - process
pool-2-thread-3 - finish
好吧,但如果我在flatMap并行化调度程序停止更改线程后,在映射中添加n>10的睡眠
public static void main(String[] args) throws InterruptedException {
Scheduler sA = Schedulers.from(Executors.newFixedThreadPool(1));
Scheduler sB = Schedulers.from(Executors.newFixedThreadPool(5));
Observable.create(s -> {
while (true) {
log("start");
s.onNext(Math.random());
sleep(10);
}
}).subscribeOn(sA)
.flatMap(r -> Observable.just(r).subscribeOn(sB))
.doOnNext(r -> sleep(15))
.doOnNext(r -> log("process"))
.subscribe((r) -> log("finish"));
}
以下是什么原因:
pool-1-thread-1 - start
pool-1-thread-1 - start
pool-2-thread-1 - process
pool-2-thread-1 - finish
pool-1-thread-1 - start
pool-1-thread-1 - start
pool-2-thread-1 - process
pool-2-thread-1 - finish
pool-1-thread-1 - start
pool-2-thread-1 - process
为什么???为什么在flatMap之后,所有元素都在同一个线程(池-2-thread-1)中处理?flatMap将所有并行任务序列化回单个线程,您可以查看此线程。试试这个
public static void main(String[] args) throws InterruptedException {
Scheduler sA = Schedulers.from(Executors.newFixedThreadPool(1));
Scheduler sB = Schedulers.from(Executors.newFixedThreadPool(5));
Observable.create(s -> {
while (!s.isUnsubscribed()) {
log("start");
s.onNext(Math.random());
sleep(10);
}
}).subscribeOn(sA)
.flatMap(r ->
Observable.just(r)
.subscribeOn(sB)
.doOnNext(r -> sleep(15))
.doOnNext(r -> log("process"))
)
.subscribe((r) -> log("finish"));
}
非常感谢。为什么我不在睡觉的情况下偷看这个线程呢?源之间存在一个不确定的发射竞争,一些线程也可能发射其他线程的元素。