Java 在SQL中获取多个计数

我希望sql查询返回所有活动和过去案例的计数。我试过这样一个问题

SELECT 
    sum(case when need_By > sysdate and status not in (30,40,50) then 1 else 0 end) AS active,
    sum(case when need_by < sysdate and status not in (30,40,50) then 1 else 0 end) AS past
FROM discrepancy
GROUP BY id;

我期待的是,

ACTIVE PAST
  1      3

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如何更改查询以获取活动记录和过去记录的计数。此外，此查询将在hibernate中执行，因此希望确保createNativeQuery工作。

通过删除

组：

SELECT sum(case when need_By > sysdate and status not in (30,40,50) then 1 else 0 end) AS active,
       sum(case when need_by < sysdate and status not in (30,40,50) then 1 else 0 end) AS past
FROM discrepancy;

编辑：

在Oracle中，最后一个是：

SELECT SUM(CASE WHEN need_By > sysdate THEN 1 ELSE 0 END) AS active,
       SUM(CASE WHEN need_by < sysdate THEN 1 ELSE 0 END) AS past
FROM discrepancy
WHERE status NOT IN (30, 40, 50);

选择SUM（当需要时为CASE\u By>sysdate，然后选择1或0 END）作为活动项，
与过去相同的总和（当需要时，按
谢谢。第一个有效。如果我尝试执行第二和第三版本，我会得到ORA-00907：缺少右括号00907。00000-“缺少右括号”*原因：*操作：@JNPW。你应该正确地标记你的问题。您使用MySQL作为标记，它不会产生ORA错误。我没有看到。MySQL是一个错误，我已经解决了。谢谢。
SELECT SUM(need_By > sysdate and status not in (30,40,50)) AS active,
       SUM(need_by < sysdate and status not in (30,40,50)) AS past
FROM discrepancy;

SELECT SUM(need_By > sysdate) AS active,
       SUM(need_by < sysdate) AS past
FROM discrepancy
WHERE status NOT IN (30, 40, 50);

SELECT SUM(CASE WHEN need_By > sysdate THEN 1 ELSE 0 END) AS active,
       SUM(CASE WHEN need_by < sysdate THEN 1 ELSE 0 END) AS past
FROM discrepancy
WHERE status NOT IN (30, 40, 50);