Java Try catch块，catch块不会重新提示用户输入新值

我是Java新手，想问你一个问题

我编写了下面的代码，其中“

numOfThreads

”应该由用户通过控制台分配一个有效的int值

但是，我希望得到这样一个结果：如果输入不正确，我们进入catch块，则应重新提示用户输入“

numothreads

”，直到其类型和范围正确

出于某种原因，我似乎进入了无限循环。你能帮忙吗？谢谢：）

---

这不是因为

nextInt

试图使用最后一个令牌。当存在无效输入时，它不能使用它。因此，下面的

nextInt

调用也无法使用它。在

numOfThreads=keyboard.nextLine（）之前写一个
keyboard.nextLine
你很好

catch(Exception e){
    System.out.println("Entry is not correct and the following exception is returned: " + e);
    // this consumes the invalid token now
    keyboard.nextLine();
    numOfThreads = keyboard.nextInt(); // It wasn´t able to get the next input as the previous was still invalid
    // I´d still rewrite it a little bit, as this keyboard.nextInt is now vulnerable to throw a direct exception to the main
}

如果
nextInt（）。。。所以再次调用
nextInt
只会再次抛出。您的try/catch非常无用。。。如果你重新编程时他们输入了错误的输入怎么办？
catch(Exception e){
    System.out.println("Entry is not correct and the following exception is returned: " + e);
    // this consumes the invalid token now
    keyboard.nextLine();
    numOfThreads = keyboard.nextInt(); // It wasn´t able to get the next input as the previous was still invalid
    // I´d still rewrite it a little bit, as this keyboard.nextInt is now vulnerable to throw a direct exception to the main
}