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Java 时间戳列表覆盖上一个时间戳_Java_Timestamp - Fatal编程技术网

Java 时间戳列表覆盖上一个时间戳

Java 时间戳列表覆盖上一个时间戳,java,timestamp,Java,Timestamp,我使用arraylist存储过去5周的时间戳列表 i.e., if today is 2014-06-09, I want to store 2014-06-02 2014-05-26 2014-05-19 2014-05-12 2014-05-05 这是我的密码 public class Test { public static void main(String ap[]) throws InterruptedException{

我使用arraylist存储过去5周的时间戳列表

   i.e., if today is 2014-06-09, I want to store 
   2014-06-02 
   2014-05-26 
   2014-05-19 
   2014-05-12       
   2014-05-05
这是我的密码

public class Test {

public static void main(String ap[]) throws InterruptedException{
List<Timestamp> ts = new ArrayList<Timestamp>();
Timestamp t = new Timestamp(new java.util.Date().getTime());
Timestamp temp = null;

for(int i=0;i<5;i++){
    t.setTime(t.getTime()-(7*24 * (long)60* (long)60) * (long)1000);
    temp = t;
    System.out.println(t);
    ts.add(temp);
    temp = null;
        }
}
}
公共类测试{
公共静态void main(字符串ap[])引发InterruptedException{
List ts=new ArrayList();
Timestamp t=new Timestamp(new java.util.Date().getTime());
时间戳temp=null;

对于(int i=0;i而言,您没有获得“新”时间戳的原因是因为您一直覆盖同一个时间戳并将其添加到列表中-因此您最终在列表中输入了5次相同的对象,最后一个值将显示在“all”中项目。您不需要
temp
-只需创建一个新的
时间戳
对象并将其添加到列表中:

    List<Timestamp> ts = new ArrayList<Timestamp>();
    Timestamp t = new Timestamp(new java.util.Date().getTime());

    for(int i=0;i<5;i++){
        t.setTime(t.getTime()-(7*24 * (long)60* (long)60) * (long)1000);
        System.out.println(t);
        ts.add(new Timestamp(t.getTime()));
    }
List ts=new ArrayList();
Timestamp t=new Timestamp(new java.util.Date().getTime());
对于(int i=0;i