Java 使用Xpath进行属性提取

我有一个XML作为Java字符串：

String abc = "<Tags  Value = '635' Type = 'Number'/>";

试试看

公共类示例{
公共静态void main（字符串[]args）抛出FileNotFoundException、XPathExpressionException{
字符串abc=“”；
InputSource文档=新的InputSource（新的StringReader（abc））；
XPath=XPathFactory.newInstance（）.newXPath（）；
XPathExpression expr=xPath.compile（“/Tags/@Value”）；
System.out.println（expr.evaluate（doc））；//635
}
}

试试看

public class Example {

    public static void main(String[] args) throws FileNotFoundException, XPathExpressionException {
        String abc = "<Tags  Value = '635' Type = 'Number'/>";
        InputSource doc = new InputSource(new StringReader(abc));
        XPath xPath = XPathFactory.newInstance().newXPath();
        XPathExpression expr = xPath.compile("/Tags/@Value");
        System.out.println(expr.evaluate(doc)); // 635
    }

}

公共类示例{
公共静态void main（字符串[]args）抛出FileNotFoundException、XPathExpressionException{
字符串abc=“”；
InputSource文档=新的InputSource（新的StringReader（abc））；
XPath=XPathFactory.newInstance（）.newXPath（）；
XPathExpression expr=xPath.compile（“/Tags/@Value”）；
System.out.println（expr.evaluate（doc））；//635
}
}

线程“main”java.net.MalformedURLException:无协议：

/Tags/@Value]

是否仔细检查了该语法？线程“main”java.net.MalformedURLException:无协议：

/Tags/@Value]

是否仔细检查了该语法？

 InputSource doc = new InputSource(abc);
 XPath xPath =  XPathFactory.newInstance().newXPath();
 XPathExpression expr = xPath.compile("/Tags/@Value");
 System.out.println(expr.evaluate(doc));

public class Example {

    public static void main(String[] args) throws FileNotFoundException, XPathExpressionException {
        String abc = "<Tags  Value = '635' Type = 'Number'/>";
        InputSource doc = new InputSource(new StringReader(abc));
        XPath xPath = XPathFactory.newInstance().newXPath();
        XPathExpression expr = xPath.compile("/Tags/@Value");
        System.out.println(expr.evaluate(doc)); // 635
    }

}