Java Android edittext:格式化数字
我有一个Java Android edittext:格式化数字,java,android,android-edittext,format,string-formatting,Java,Android,Android Edittext,Format,String Formatting,我有一个edittext,如果我输入的数字是100000,结果必须是100.000,如果我输入的是1000000,结果必须是1.000.000 从最后到开始的每3个字符后面必须有一个“” 这是我的密码: tambah = (EditText)rootView.findViewById(R.id.total); tambah.setOnFocusChangeListener(new OnFocusChangeListener(){ public void onFocusChange(
edittext
,如果我输入的数字是100000
,结果必须是100.000
,如果我输入的是1000000
,结果必须是1.000.000
从最后到开始的每3个字符后面必须有一个“
”
这是我的密码:
tambah = (EditText)rootView.findViewById(R.id.total);
tambah.setOnFocusChangeListener(new OnFocusChangeListener(){
public void onFocusChange(View v, boolean hasFocus) {
// ...
}
你应使用:
使用editText.setContextChangeListener()并检查每次位置是否为3的倍数,在那里放一个(点)..这是我用来输入美元的东西。它确保在任何时候小数点后只有2位。您应该能够通过删除$符号使其适应您的需要
amountEditText.setRawInputType(Configuration.KEYBOARD_12KEY);
amountEditText.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {}
public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(!s.toString().matches("^\\$(\\d{1,3}(\\,\\d{3})*|(\\d+))(\\.\\d{2})?$"))
{
String userInput= ""+s.toString().replaceAll("[^\\d]", "");
StringBuilder cashAmountBuilder = new StringBuilder(userInput);
while (cashAmountBuilder.length() > 3 && cashAmountBuilder.charAt(0) == '0') {
cashAmountBuilder.deleteCharAt(0);
}
while (cashAmountBuilder.length() < 3) {
cashAmountBuilder.insert(0, '0');
}
cashAmountBuilder.insert(cashAmountBuilder.length()-2, '.');
cashAmountBuilder.insert(0, '$');
amountEditText.setText(cashAmountBuilder.toString());
// keeps the cursor always to the right
Selection.setSelection(amountEditText.getText(), cashAmountBuilder.toString().length());
}
}
});
amountEditText.setRawInputType(配置键盘键);
amountEditText.addTextChangedListener(新的TextWatcher(){
公共无效后文本更改(可编辑的s){}
public void beforeTextChanged(字符序列s、int start、int count、int after){}
public void onTextChanged(字符序列、int start、int before、int count){
如果(!s.toString().matches(“^\\$(\\d{1,3}(\\,\\d{3})*\\(\\d+)(\\\.\\d{2})?$”)
{
字符串userInput=“”+s.toString().replaceAll(“[^\\d]”,“”);
StringBuilder cashAmountBuilder=新的StringBuilder(用户输入);
while(cashAmountBuilder.length()>3&&cashAmountBuilder.charAt(0)='0'){
cashAmountBuilder.deleteCharAt(0);
}
while(cashAmountBuilder.length()<3){
cashAmountBuilder.insert(0,'0');
}
插入(cashAmountBuilder.length()-2',”;
cashAmountBuilder.insert(0,“$”);
amountEditText.setText(cashAmountBuilder.toString());
//将光标始终保持在右侧
Selection.setSelection(amountEditText.getText(),cashAmountBuilder.toString().length());
}
}
});
首先将字符串格式化为%,d
格式,然后将所有(,)替换为(.),如下所示
String formatedString = (String.format("%,d", 1000000)).replace(',', '.');
Log.d("Fomated String", formatedString);
输出:
D/Fomated String(20323): 1.000.000
用下面的循环来做怎么样
String Number=1000000;
final int THREE=3;
int noOfPoints,length,Start=0,End=0;
length=Number.length();
noOfPoints=length%THREE;
if(noOfPoints*THREE==length)
noOfPoints--;
String OutPut="";
for(int Count=0;Count<=noOfPoints;Count++)
{
Start=End;
if(Count==0)
End=length-(THREE*noOfPoints);
else
End=Start+THREE;
if(Count!=noOfPoints)
OutPut+=Number.substring(Start,End)+".";
else
OutPut+=Number.substring(Start,End);
}
字符串编号=1000000;
最终int 3=3;
int noOfPoints,长度,开始=0,结束=0;
长度=数字。长度();
noOfPoints=长度%3;
if(noOfPoints*THREE==长度)
无点--;
字符串输出=”;
对于(int Count=0;Count,这里是另一个答案。希望它能帮助您,简单,并且可以格式化给定参数的大小(formatsize,loook在示例调用中)
看一看
/**
*
*@param输入
*@param formatsize
*@返回
*/
关于…是的,你是对的,但我需要一个逻辑来格式化字符串,我使用2位你可以设置3位总是欢迎的伙计,只要尝试一下我希望它对你有用:)我是android初学者,我想问,什么函数:if(!s.toString().matches(^\$)(\\d{1,3}(\\,\\d{3})*(\\d+)(\\d+)(\\\\\\.\\d{2})$)这是一个正则表达式。请阅读有关此的详细信息给我完整的逻辑,请帮助我。检查位置%3==0我认为edittext上没有事件SetContextChangeListener()
String Number=1000000;
final int THREE=3;
int noOfPoints,length,Start=0,End=0;
length=Number.length();
noOfPoints=length%THREE;
if(noOfPoints*THREE==length)
noOfPoints--;
String OutPut="";
for(int Count=0;Count<=noOfPoints;Count++)
{
Start=End;
if(Count==0)
End=length-(THREE*noOfPoints);
else
End=Start+THREE;
if(Count!=noOfPoints)
OutPut+=Number.substring(Start,End)+".";
else
OutPut+=Number.substring(Start,End);
}
public String format(String input, int formatsize) {
String formattedNumberString = "";
int len = input.length();
if (len < formatsize)
return input;
if (formatsize < 2) {
System.out.println("Opppps");
return "";
}
for (int i = 0; i < len; i += formatsize) {
if (i < formatsize) {
formattedNumberString = input.substring(input.length()
- formatsize - 1, input.length() - 1);
} else {
if (len - i <= formatsize) {
formattedNumberString = input + "." + formattedNumberString;
} else {
formattedNumberString = input.substring(input.length()
- formatsize - 1, input.length() - 1)
+ "." + formattedNumberString;
}
}
if (input.length() >= formatsize)
input = input.substring(0, len - i - formatsize);
}
return formattedNumberString;
}
NumberFormatterClass nfc = new NumberFormatterClass();
System.out.println(nfc.format("1032432420000000000000", 3));
System.out.println(nfc.format("1032432420000000000000", 4));
System.out.println(nfc.format("1032432420000000000000", 5));
System.out.println(nfc.format("1032432420000000000000", 2));