Java 服务器返回了HTTP响应代码:406 a URL

Java 服务器返回了HTTP响应代码:406 a URL,java,web-crawler,jsoup,httpurlconnection,Java,Web Crawler,Jsoup,Httpurlconnection,我正在使用Java和HttpURLConnection编写一个web爬虫程序,这是我得到的错误: java.io.IOException: Server returned HTTP response code: 406 for URL: https://www.mkyong.com/kotlin/kotlin-how-to-loop-a-map/ at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Sour

我正在使用Java和HttpURLConnection编写一个web爬虫程序,这是我得到的错误:

java.io.IOException: Server returned HTTP response code: 406 for URL: https://www.mkyong.com/kotlin/kotlin-how-to-loop-a-map/
at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source)
at testing.HttpURLConnectionGo.sendGet(HttpURLConnectionGo.java:34)
at testing.DefinitelyNotSpiderLeg.crawl(DefinitelyNotSpiderLeg.java:55)
at testing.DefinitelyNotSpider.search(DefinitelyNotSpider.java:33)
at testing.Test.main(Test.java:9)
这是我用于连接的方法:

// HTTP GET request
public String sendGet(String url) throws Exception {

    URL obj = new URL(url);
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

    // optional default is GET
    con.setRequestMethod("GET");

    //add request header
    con.setRequestProperty("User-Agent", USER_AGENT);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();
    return response.toString();
}
然后我使用Jsoup在另一个类中获取字符串:

String html = http.sendGet(url);
Document doc = Jsoup.parse(html);
为什么会出现此错误?

根据和,HTTP 406的状态为“不可接受”。Mozilla参考继续说,这种错误非常罕见,通常意味着

指示与可接受值列表匹配的响应 无法提供在Accept字符集和Accept语言中定义的

您可以尝试在请求中设置这些标题

也可能是您正在点击的URL具有某种机器人或爬虫程序检测逻辑,并且返回406,因为该行为“不可接受”。该用例不是理想的错误代码,但它是有意义的