Java 如何获取包含在单个字符串中的变量名及其值？

如果单个字符串中包含信息，如何获取字符串变量名并为其赋值

我有这样一个字符串：

"id: 123487, street1: Stanton, street2: Gateway, street3: Hawkins, city: Horizon"

我试图达到的结果是：
id=“123487”
street1=“斯坦顿”
street2=“网关”
street3=“霍金斯”
城市=“地平线”

到目前为止，我掌握的是以下代码：

String scannedData = "id: 123487, street1: Stanton, street2: Gateway, street3: Hawkins, city: Horizon"


String[] data = scannedData.split(",");
for (String result1 : data) {
    Toast.makeText(scanQrActivity.this,
            result1, Toast.LENGTH_LONG).show();
}

因此，我能够向使用Toast的用户显示由逗号分隔的字符串，我有这样一个：
“id:123487”
“街道1：斯坦顿”
“街道2：网关”
“街3：霍金斯”
“城市：地平线”

也许我可以先创建5个变量，然后以某种方式只获取值，因此在for循环中，我可以将每个值分配给每个变量？
但我不知道如何，你能帮我实现我的目标吗？
谢谢

---

我创建了一个

Location

类，它将保存我们要分析的数据

public class Location {

    private int id;

    private String street1, street2, street3, city;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getStreet1() {
        return street1;
    }

    public void setStreet1(String street1) {
        this.street1 = street1;
    }

    public String getStreet2() {
        return street2;
    }

    public void setStreet2(String street2) {
        this.street2 = street2;
    }

    public String getStreet3() {
        return street3;
    }

    public void setStreet3(String street3) {
        this.street3 = street3;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }
}

现在，我们可以使用以下方法将输入字符串解析为

位置

对象

public static Location parseLocation(String input) {
    // Get the input and split it into an array of "key: value" strings.
    String[] splitInput = input.split(", ");

    // Create an array to hold the actual key-values.
    String[][] keyValues = new String[splitInput.length][2];

    // Split each "key: value" string into its consisting parts.
    for (int i = 0; i < splitInput.length; i++) {
        keyValues[i] = splitInput[i].split(": ");
    }

    // Create a Location object to populate.
    Location location = new Location();

    // Find the keys & values from the input that you're looking for.
    for (String[] keyValue : keyValues) {

        // Switch on the key.
        switch (keyValue[0]) {
            case "id":
                location.setId(Integer.valueOf(keyValue[1]));
                break;

            case "street1":
                location.setStreet1(keyValue[1]);
                break;

            case "street2":
                location.setStreet2(keyValue[1]);
                break;

            case "street3":
                location.setStreet3(keyValue[1]);
                break;

            case "city":
                location.setCity(keyValue[1]);
                break;
        }
    }
    return location;
}

---

谢谢你们的帮助，你们给了我很棒的建议，最后，我用了一种更简单的方式，它可能不是最好的编码，但我仍在学习，我认为我的目标是像你们一样编码，所以你们的答案真的帮助我认识到我还有很多东西要学

    String scannedData = "id: 123487, street1: Stanton, street2: Gateway, street3: Hawkins, city: Horizon"

    String[] data = scannedData .split(",");
    String id = null;
    String street1 = null;
    String street2 = null;
    String street3 = null;
    String city = null;
    for (String result : data) {

        id = data[0].replace("id: ", "");
        street1 = data[1].replace("street1: ", "");
        street2 = data[2].replace("street2: ", "");
        street3 = data[3].replace("street3: ", "");
        city = data[4].replace("city: ", "");
    }

---

然后我用Toast展示了每个变量。

你问的问题不是特别清楚，但是你可以进一步将“str:Fnord”字符串拆分为两个字符串的数组。好的，我明白了，我正在尝试创建字符串变量并给它们赋值，例如，如果我有这个字符串：“city:Horizon，street1:Stanton”我想要一个名为city的字符串变量，其值等于“Horizon”，并对street1执行相同的操作，以此类推。所以如果我理解你的建议，我会再次分手。但这一次被“：”分开了？

public static void main(String[] args) {
    String   input    = "id: 123487, street1: Stanton, street2: Gateway, street3: Hawkins, city: Horizon";
    Location location = parseLocation(input);

    System.out.println(String.format("id: %d\n"
            + "street1: %s\n"
            + "street2: %s\n"
            + "street3: %s\n"
            + "city: %s", location.getId(), 
            location.getStreet1(), location.getStreet2(), 
            location.getStreet3(), location.getCity()));
}

    String scannedData = "id: 123487, street1: Stanton, street2: Gateway, street3: Hawkins, city: Horizon"

    String[] data = scannedData .split(",");
    String id = null;
    String street1 = null;
    String street2 = null;
    String street3 = null;
    String city = null;
    for (String result : data) {

        id = data[0].replace("id: ", "");
        street1 = data[1].replace("street1: ", "");
        street2 = data[2].replace("street2: ", "");
        street3 = data[3].replace("street3: ", "");
        city = data[4].replace("city: ", "");
    }