Java 如何从HTTP请求中获取正确的数据

我试图使用一个简单的HTTP请求和Java中的get方法从stackoverflow api获取用户信息

我以前使用过这段代码，使用get方法获取另一个HTTP数据，没有问题：

    URL obj;
    StringBuffer response = new StringBuffer();
    String url = "http://api.stackexchange.com/2.2/users?inname=HCarrasko&site=stackoverflow";
        try {
        obj = new URL(url);
        HttpURLConnection con = (HttpURLConnection) obj.openConnection();
        con.setRequestMethod("GET");
        int responseCode = con.getResponseCode();
        System.out.println("\nSending 'GET' request to URL : " + url);
        System.out.println("Response Code : " + responseCode);
        BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
        String inputLine;

        while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
        }

        in.close();
        System.out.println(response.toString());
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

但在这种情况下，当我打印

响应

变量时，我得到的只是一些奇怪的符号，如下所示：

�mRM��0�+�N!���FZq�\�pD�z�:V���JX���M��̛yO^���뾽�g�5J&� �9�YW�%c`do���Y'��nKC38<A�&It�3��6a�,�,]���`/{�D����>6�Ɠ��{��7tF ��E��/����K���#_&�yI�a�v��uw}/�g�5����TkBTķ���U݊c���Q�y$���$�=ۈ��ñ���8f�<*�Amw�W�ـŻ��X$�>'*QN�?�<v�ݠ FH*��Ҏ5����ؔA�z��R��vK���"���@�1��ƭ5��0��R���z�ϗ/�������^?r��&�f��-�OO7���������Gy�B���Rxu�#:0�xͺ}�\�����

---

�mRM��0�+�N���FZq�\�pD�Z�:v���JX���M��̛y  O^���뾽�G�5J&� �9�YW�%c'do���Y'��nKC386�Ɠ��{��7tF��E��/����K���#_&�彝族�A.�v��uw}/�G�5.����TkBTķ���U݊c���Q�y$���$�=ۈ��ñ���8f�'*QN�?� 内容可能是GZIP编码/压缩的。以下是我在所有使用HTTP的基于Java的客户机应用程序中使用的一般代码片段，旨在解决这个问题：

// Read in the response
// Set up an initial input stream:
InputStream inputStream = fetchAddr.getInputStream(); // fetchAddr is the HttpURLConnection

// Check if inputStream is GZipped
if("gzip".equalsIgnoreCase(fetchAddr.getContentEncoding())){
    // Format is GZIP
    // Replace inputSteam with a GZIP wrapped stream
    inputStream = new GZIPInputStream(inputStream);
}else if("deflate".equalsIgnoreCase(fetchAddr.getContentEncoding())){
    inputStream = new InflaterInputStream(inputStream, new Inflater(true));
} // Else, we assume it to just be plain text

BufferedReader sr = new BufferedReader(new InputStreamReader(inputStream));
String inputLine;
StringBuilder response = new StringBuilder();
// ... and from here forward just read the response...

这依赖于以下导入：
java.util.zip.gzip输入流
java.util.zip.Inflater
；和
java.util.zip.InflateInputStream
内容可能是GZIP编码/压缩的。以下是我在所有使用HTTP的基于Java的客户机应用程序中使用的一般代码片段，旨在解决这个问题：

// Read in the response
// Set up an initial input stream:
InputStream inputStream = fetchAddr.getInputStream(); // fetchAddr is the HttpURLConnection

// Check if inputStream is GZipped
if("gzip".equalsIgnoreCase(fetchAddr.getContentEncoding())){
    // Format is GZIP
    // Replace inputSteam with a GZIP wrapped stream
    inputStream = new GZIPInputStream(inputStream);
}else if("deflate".equalsIgnoreCase(fetchAddr.getContentEncoding())){
    inputStream = new InflaterInputStream(inputStream, new Inflater(true));
} // Else, we assume it to just be plain text

BufferedReader sr = new BufferedReader(new InputStreamReader(inputStream));
String inputLine;
StringBuilder response = new StringBuilder();
// ... and from here forward just read the response...

这依赖于以下导入：
java.util.zip.gzip输入流
java.util.zip.Inflater
；和
java.util.zip.InflateInputStream