Java 如何检查ArrayList是否<；字符串>；是否包含字符串数组中的任何元素？

在Android中，我想执行一个if语句来检查ArrayList是否包含字符串数组中的任何元素？ e、 g

检查singingGroup中的任何元素是否也包含在Winners[]中

你可以用

Collections.disjoint(singingGroup, Arrays.asList(Winners));

要测试，这两个参数没有公共元素。（另见）

---

结果的否定似乎就是您所要寻找的。

您也可以这样检查：

String Winners[] = {"Jennifer", "Patrick", "Peter", "Parker"};

        ArrayList<String> singingGroup  = new ArrayList<String>();

        singingGroup.add("Patrick");

        singingGroup.add("Jane");

        singingGroup.add("Joe");

        singingGroup.add("Susan");

        singingGroup.add("Amy");

        for(int i=0; i< Winners.length;i++)
        {
            if(singingGroup.contains(Winners[i]))
            {
                System.out.println("duplicate");
            }
        }

stringwinners[]={“珍妮弗”、“帕特里克”、“彼得”、“帕克”}；
ArrayList singingGroup=新建ArrayList（）；
singingGroup.add（“Patrick”）；
singingGroup.add（“Jane”）；
singingGroup.add（“Joe”）；
singingGroup.add（“Susan”）；
singingGroup.add（“艾米”）；
for（int i=0；i

Collections.disjoint是存档此文件的一种方法，但也可以使用retainal（）方法

仅保留此列表中包含在指定集合中的元素（可选操作）。换句话说，从该列表中删除指定集合中不包含的所有元素

案例一：singingGroup中的元素不包含在Winners[] 案例二：singingGroup的元素也包含在Winners[] 您可以使用Apache Commons提供的类

使用交集方法（如果要对公共图元执行某些操作，此方法很有用）：

//for循环非常适合检查元素i是否=元素i
int i=0；
int loopCount=0；
while（loopCount

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这不是最理想的代码，但如果您急需它，这将起作用

是否尝试防止重复？是。如果两个指定集合没有共同元素，则Collections.disjoint返回true。

Collections.disjoint(singingGroup, Arrays.asList(Winners));

String Winners[] = {"Jennifer", "Patrick", "Peter", "Parker"};

        ArrayList<String> singingGroup  = new ArrayList<String>();

        singingGroup.add("Patrick");

        singingGroup.add("Jane");

        singingGroup.add("Joe");

        singingGroup.add("Susan");

        singingGroup.add("Amy");

        for(int i=0; i< Winners.length;i++)
        {
            if(singingGroup.contains(Winners[i]))
            {
                System.out.println("duplicate");
            }
        }

String Winners[] = {"Jennifer", "Steven", "Peter", "Parker"};
ArrayList<String> singingGroup  = new ArrayList<String>();

singingGroup.add("Patrick");
singingGroup.add("Jane");
singingGroup.add("Joe");
singingGroup.add("Susan");
singingGroup.add("Amy");

List<String> WinnerList = new ArrayList<>(Arrays.asList(Winners));
WinnerList.retainAll(singingGroup);
System.out.println("retainList = " + WinnerList);

list1 = []

String Winners[] = {"Jennifer", "Steven", "Peter", "Parker"};
ArrayList<String> singingGroup  = new ArrayList<String>();

singingGroup.add("Steven");
singingGroup.add("Jane");
singingGroup.add("Joe");
singingGroup.add("Susan");
singingGroup.add("Jennifer");

List<String> WinnerList = new ArrayList<>(Arrays.asList(Winners));
WinnerList.retainAll(singingGroup);
System.out.println("retainList = " + WinnerList);

retainList = [Jennifer, Steven]

Collection<String> intersection = CollectionUtils.intersection(singingGroup, Arrays.asList(Winners));

if (intersection.size() > 0){

    // At least one element contained in the intersection
}

if (CollectionUtils.containsAny(singingGroup, Arrays.asList(Winners))){

    // True if at least one common element exists in both lists  
}

//for loop would be perfect to check if element i = element i

int i =0;
int loopCount = 0;
while(loopCount < Winners.lenght)
{
  for(int i =0; i < singingGroup.length; i++)
  {
    if(Winners[loopCount] == singingGroup[i])
    {
    System.out.println(Winners[loopCount] + "is apart of the winners");
    }//end of comparing if

    if(i == singing.Group.length)
    { 
    loopCount ++;
    } //end of i == singingGroup

  }//end of for loop

}//end of while  loop