Java 如何在8秒内完成Ads_全屏活动，并在活动结束后享用午餐？

启动屏幕的两种情况

如果启用ads，则启动屏幕时间将为2秒，ads_全屏时间将为8秒，然后将出现最终的主要活动

如果未启用ads，则启动屏幕时间将为5秒，然后主要活动将开始

这是启动屏幕的代码

 new Handler().postDelayed(new Runnable() {
      @Override
      public void run() {
          Intent i;
          if (prefManager.isFirstTimeLaunch()){
              i = new Intent(SplashScreen.this,WelcomeActivity.class);
              prefManager.setFirstTimeLaunch(false);
          }else if(bn_bstatus.equals("enable")) {
              i = new Intent(SplashScreen.this,Ads_Fullscreen.class);

          }else{
              i = new Intent(SplashScreen.this,MainActivity.class);
          }
          startActivity(i);
          finish();
      }
  },SPLASH_TIME_OUT);

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将默认值

SPLASH\u TIME\u OUT

设置为

5000

毫秒

public final int SPLASH_TIME_OUT = 5000;

用于SplashScreen活动

用于全屏活动的广告

---

谢谢@Dhruv你是最棒的，回答很有魅力！

final Intent intent;
if (ads.enable()) {
    intent = new Intent(SplashScreen.this, WelcomeActivity.class);
    prefManager.setFirstTimeLaunch(false);
} else if (bn_bstatus.equals("enable")) {
    intent = new Intent(SplashScreen.this, Ads_Fullscreen.class);
    SPLASH_TIME_OUT = 2000;
} else {
    intent = new Intent(SplashScreen.this, MainActivity.class);
}
new Handler().postDelayed(new Runnable() {
    @Override
    public void run() {
        startActivity(intent);
        finish();
    }
}, SPLASH_TIME_OUT);

SPLASH_TIME_OUT = 8000;
new Handler().postDelayed(new Runnable() {
        @Override
        public void run() {
            // start MainActivity
        }
    }, SPLASH_TIME_OUT);