Java 如何创建一组字符串，其中每个字符串都有1000个要在Oracle查询表达式中使用的客户id

我的输入为客户编号CSR\U ID BigDecimal11,0。以下代码失败，因为Oracle查询表达式的限制为1000：

//Start of the code
 String cust_ids = null;
 int cnt_cust    = 0;
 java.util.StringJoiner joiner = new java.util.StringJoiner(","," ( "," ) ");

 //This is a loop which gets CSR_ID as input:
   joiner.add(row5.CSR_ID.toString());
    cnt_cust++;

//End of the code
   System.out.println(joiner); // (1,2,3,...,100045)
   cust_ids = joiner.toString();  

查询如下所示：

"select col1, col2 from customers where cust_id in " +  
"(1,2,3,...,100045)";

我想将其拆分如下：

"select col1, col2 from customers where" +  
" cust_id in (1,2,3...,1000)" +
" or cust_id in (1001,.....2000)" +
.....   ;

如何以1000个customer-id的批量构建此查询表达式。

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注意：客户id不是连续的，而是随机值

我认为您可以利用以下多列比较：

select col1, col2 from customers where cust_id in   
(1,2,3,...,100045); -- This will fail

select col1, col2 from customers where (cust_id,1) in   
((1,1),(2,1),(3,1),...,(100045,1)); -- This will work

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干杯

一个没有优化的解决方案如下所示，我认为在Java8中使用Stream有更优雅的方法

其概念是将客户ID转换为列表，然后您可以使用所需的块大小划分列表

    int blockSize = 1000;
    List<String> cust_idsList = Arrays.asList(cust_ids.substring(1, cust_ids.length()-1).split(","));
    System.out.println(cust_idsList.size());

    StringBuilder sb = new StringBuilder();
    sb.append("select col1, col2 from customers where cust_ids in (");
    for (int i = 0; i < cust_idsList.size(); i++) {
        sb.append(cust_idsList.get(i)).append(",");
        if (i !=0 && i%blockSize == blockSize-1) {
            sb.setLength(sb.length()-1);

            if (i != cust_idsList.size()-1) {
                sb.append(")\n or cust_ids in (");
            }
        }
    }
    sb.setLength(sb.length()-1);
    sb.append(")");

    System.out.println(sb.toString());

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谢谢，我想用java构建这个字符串。如何做到这一点。不是Java专家。很抱歉不要使用字符串连接来构建查询，请使用参数化查询，如果需要传递值数组，请绑定或使用临时表。