Java 爪哇语&引用；（“预期”编译器错误

我是Java的初学者，在通过书本学习了几次这种语言之后，我决定编写一个简单的程序，通过用字母替换数字来“加密”字符串，反之亦然。它还没有完成，并且有一些相当大的限制，但它应该按原样工作

守则：

import java.util.Scanner;

class Chiffrator {
public static void main (String args[]) {

    Scanner input = new Scanner(System.in); // Initializing keyboard scanner, like arrays (Scanner [name] = new Scanner(System.in)

    String initial_code; // Initializing the string into which the text will be entered
    System.out.println ("Enter initial code: ");
    initial_code = input.next(); // Initializing input process, with syntax [string_name] = [scanner_name].next()

    char letters[] = {a,b,c,d,e,f,g,h,i,j};
    numbers = new numbers[9];
    int i,j,k;


    for (i=0; i=9; i++) {
        numbers[i] = i;
        i++;
    } 


    for (k=0; k=init_code.length(); k++) { // .length() is a method!
        if initial_code.contains(numbers))
            numbers[k] = letters[k];
        else if initial_code.contains(letters))
            letters[k] = numbers [k];
        k++;
    }       


    System.out.println ("Your chiffred code is " + initial_code);
}
}

它不工作。当我试图通过Mac上的终端编译它时，有两个错误：

Chiffrator.java:24: error: '(' expected
        if initial_code.contains(numbers))
          ^
Chiffrator.java:26: error: '(' expected
        else if initial_code.contains(letters))
               ^

若我尝试插入那个些括号，编译器会说我的代码中有20个错误

Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                      ^
symbol:   variable a
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                        ^
symbol:   variable b
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                          ^
symbol:   variable c
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                            ^
symbol:   variable d
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                              ^
symbol:   variable e
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                                ^
symbol:   variable f
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                                  ^
symbol:   variable g
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                                    ^
symbol:   variable h
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                                      ^
symbol:   variable i
location: class Chiffrator
Chiffrator.java:12: error: cannot find symbol
    char letters[] = {a,b,c,d,e,f,g,h,i,j};
                                        ^
symbol:   variable j
location: class Chiffrator
Chiffrator.java:13: error: cannot find symbol
    numbers = new numbers[9];
    ^
symbol:   variable numbers
location: class Chiffrator
Chiffrator.java:13: error: cannot find symbol
    numbers = new numbers[9];
                  ^
symbol:   class numbers
location: class Chiffrator
Chiffrator.java:18: error: incompatible types: int cannot be converted to boolean
    for (i=0; i=9; i++) {
               ^
Chiffrator.java:19: error: cannot find symbol
        numbers[i] = i;
        ^
symbol:   variable numbers
location: class Chiffrator
Chiffrator.java:24: error: cannot find symbol
    for (k=0; k=init_code.length(); k++) // .length() is a method!
                ^
symbol:   variable init_code
location: class Chiffrator
Chiffrator.java:24: error: incompatible types: int cannot be converted to boolean
    for (k=0; k=init_code.length(); k++) // .length() is a method!
               ^
Chiffrator.java:25: error: cannot find symbol
        if (cont_let = (initial_code.contains(numbers)))
                                              ^
symbol:   variable numbers
location: class Chiffrator
Chiffrator.java:26: error: cannot find symbol
            numbers[k] = letters[k];
            ^
symbol:   variable numbers
location: class Chiffrator
Chiffrator.java:27: error: incompatible types: char[] cannot be converted to CharSequence
        else if (cont_num = (initial_code.contains(letters)))
                                                   ^
Chiffrator.java:28: error: cannot find symbol
            letters[k] = numbers [k];
                         ^
symbol:   variable numbers
location: class Chiffrator
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
20 errors

---

谢谢您的帮助！

我看到您的代码中有很多问题

第一名：

char letters[] = {a,b,c,d,e,f,g,h,i,j};

numbers = new numbers[9];

 for (i=0; i=9; i++) {
           ^^^^
    numbers[i] = i;
    i++;
} 

应该是,

char letters[] = {'a' ,'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j'};

第二名：

char letters[] = {a,b,c,d,e,f,g,h,i,j};

numbers = new numbers[9];

 for (i=0; i=9; i++) {
           ^^^^
    numbers[i] = i;
    i++;
} 

您在哪里声明编号？您是否在寻找以下内容

int[] numbers = new int[9];

第三名：

char letters[] = {a,b,c,d,e,f,g,h,i,j};

numbers = new numbers[9];

 for (i=0; i=9; i++) {
           ^^^^
    numbers[i] = i;
    i++;
} 

可能是,

for (i=0; i<=9; i++) {

数字4:什么是

init\u code

？不是

initial\u code

第5项：在

if

和

else if

条件周围加括号，如下所示：

if (initial_code.contains(numbers))
  ^^^

以及

---

建议：请先学习JAVA编程的基本语法。

您的代码有太多的问题，如其他答案中所列，下面是一个没有编译错误的代码版本，但我不知道您在代码中尝试做什么，我很确定无论您尝试什么，您都做得不对。 学习愉快

import java.util.Scanner;

class Chiffrator {
    public static void main(String args[]) {

        Scanner input = new Scanner(System.in); // Initializing keyboard
                                                // scanner, like arrays (Scanner
                                                // [name] = new
                                                // Scanner(System.in)

        String initial_code; // Initializing the string into which the text will
                                // be entered
        System.out.println("Enter initial code: ");
        initial_code = input.next(); // Initializing input process, with syntax
                                        // [string_name] = [scanner_name].next()

        char letters[] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j' };
        int[] numbers = new int[9];
        int i, j, k;

        for (i = 0; i <= 9; i++) {
            numbers[i] = i;
            i++;
        }

        for (k = 0; k <= initial_code.length(); k++) { // .length() is a method!
            if (initial_code.contains(numbers.toString()))
                numbers[k] = letters[k];
            else if (initial_code.contains(letters.toString()))
                letters[k] = (char) numbers[k];
            k++;
        }

        System.out.println("Your chiffred code is " + initial_code);
    }
}

import java.util.Scanner；
类切碎机{
公共静态void main（字符串参数[]）{
扫描仪输入=新扫描仪（System.in）；//初始化键盘
//扫描仪，如阵列（扫描仪）
//[名称]=新建
//扫描仪（System.in）
String initial_code；//初始化文本将插入的字符串
//入围
System.out.println（“输入初始代码：”）；
initial_code=input.next（）；//使用语法初始化输入进程
//[string\u name]=[scanner\u name].next（）
字符字母[]={a'，b'，c'，d'，e'，f'，g'，h'，i'，j'}；
整数[]个数=新整数[9]；
int i，j，k；
对于（i=0；i）您缺少对
if
和
else if
条件的偏执，其他19个错误是什么？if语句的条件必须包含在if（…）大括号中，在将这些大括号放入if语句后，如果您发现任何类型的错误，请发布这些错误的堆栈跟踪（19个错误）。您的代码有太多问题，而缺少“（”只是其中之一