Java Json Http Post Android

Java Json Http Post Android,java,c#,android,json,web-services,Java,C#,Android,Json,Web Services,我正在将json数据发布到我的c#服务堆栈web服务中 try { // 1. create HttpClient HttpClient httpclient = new DefaultHttpClient(); // 2. make POST request to the given URL HttpPost httpPost = new HttpPost(url); String json = "";

我正在将json数据发布到我的c#服务堆栈web服务中

try {

        // 1. create HttpClient
        HttpClient httpclient = new DefaultHttpClient();

        // 2. make POST request to the given URL
        HttpPost httpPost = new HttpPost(url);

        String json = "";


        // 3. build jsonObject
        JSONObject jsonObject = new JSONObject();
        jsonObject.accumulate("CustomerLine1", worksheet.getCustomerLine1());
        jsonObject.accumulate("CustomerLine2", worksheet.getCustomerLine2());
        jsonObject.accumulate("CustomerLine3", worksheet.getCustomerLine3());
        jsonObject.accumulate("Status", worksheet.getStatus());

        // 4. convert JSONObject to JSON to String
        json = jsonObject.toString();

        Log.d("dasd", json);

        // ** Alternative way to convert Person object to JSON string usin Jackson Lib 
        // ObjectMapper mapper = new ObjectMapper();
        // json = mapper.writeValueAsString(person); 

        // 5. set json to StringEntity
        StringEntity se = new StringEntity(json);

        // 6. set httpPost Entity
        httpPost.setEntity(se);



        // 7. Set some headers to inform server about the type of the content
        httpPost.setHeader("Accept", "application/json");
        httpPost.setHeader("Content-type", "application/json");

        // 8. Execute POST request to the given URL
        HttpResponse httpResponse = httpclient.execute(httpPost);

        // 9. receive response as inputStream
        inputStream = httpResponse.getEntity().getContent();
我从Log.d(dasd,json)得到的响应;是

这是有效的json。然而,我从我的Web服务得到的回应是

{"responseStatus":{"message":"{CustomerLine1:gh,CustomerLine2:dg,CustomerLine3:eg,Status:0}"}
这是无效的,我不知道为什么

下面是Webservice snippit

    [EnableCors(allowedMethods: "POST")]
public class WorksheetService : Service
{
    public object Any(String Json)
    {
        var rs = new ResponseStatus()
        {
            Message = Json
        };

        return new WorksheetsResponse { ResponseStatus = rs };
    }
}
谢谢

**更新**

我正在将一个Json字符串从我的android应用程序传递到我的API,并对其进行反序列化

        public object Any(String Json)
    {
        var mn = JsonSerializer.DeserializeFromString<Worksheets>(Json);

        var rs = new ResponseStatus()
        {
            Message = Json
        };

        return new WorksheetsResponse { ResponseStatus = rs };
    }
而不是

{"CustomerLine1":"gh","CustomerLine2":"dg","CustomerLine3":"eg","Status":0}

return语句告诉服务以这种方式返回json。如果希望嵌套对象返回JSON而不是字符串,可以执行以下操作:

public class WorksheetService : Service
    {
        public object Any(JsonObject Json) 
        {
            var rs = new ResponseStatus()
            {
                Message = Json
            };

            return new WorksheetsResponse { ResponseStatus = rs }; 
        }
    }
如果您只是想要记录的原始json字符串,那么不要将其包装在ResponseStatus对象中返回

public class WorksheetService : Service
        {
            public object Any(JsonObject Json) 
            {
                return Json; 
            }
        }

你在用“mn”对象做什么?这段代码仍然显示Message=Json,它是一个字符串而不是一个JsonObject。它应该用发布的值填充Worksheets类。
public class WorksheetService : Service
    {
        public object Any(JsonObject Json) 
        {
            var rs = new ResponseStatus()
            {
                Message = Json
            };

            return new WorksheetsResponse { ResponseStatus = rs }; 
        }
    }
public class WorksheetService : Service
        {
            public object Any(JsonObject Json) 
            {
                return Json; 
            }
        }