Java SocketTimeoutException-GAE

这是我应该创建WebClient实例的完整代码，但是它不断抛出

SocketTimeoutException

：

@Override
protected int doHandle(Request request, Response response) {

    HttpServletRequest servletRequest = ServletUtils.getRequest(request);
    HttpServletResponse servletResponse = ServletUtils.getResponse(response);

    String query = servletRequest.getQueryString();
    // Only process calls to the main HTML page, and the empty one if desired
    final String requestURI = servletRequest.getRequestURI();
    if(query == null || !query.contains(ESCAPED_FRAGMENT_FORMAT1)){
        super.doHandle(request, response);
    } else {
        String reqUrl = servletRequest.getRequestURL().toString();
        String queryString = servletRequest.getQueryString();
        if (queryString != null) {
            reqUrl += "?" + queryString;
        }
        try {
            StringBuilder pageNameSb = new StringBuilder("http://");
            pageNameSb.append(servletRequest.getServerName());
            if (servletRequest.getServerPort() != 0) {
                pageNameSb.append(":");
                pageNameSb.append(servletRequest.getServerPort());
            }
            pageNameSb.append(requestURI);
            queryString = rewriteQueryString(queryString);
            pageNameSb.append(queryString);
            String pageName = pageNameSb.toString();
            LOG.info( "Crawl filter encountered escaped fragment, will open: " + pageName );
            // Setup the headless browser
            WebClient webClient = new WebClient();
            webClient.setWebConnection(new UrlFetchWebConnection(webClient));
            webClient.setThrowExceptionOnScriptError(false);
            webClient.setJavaScriptEnabled(true);
            HtmlPage page = webClient.getPage(reqUrl);
            webClient.setTimeout(GAE_PUMP_TIME);
            PrintWriter out = servletResponse.getWriter();
            out.print(page.asXml());
            webClient.closeAllWindows();
            out.close();
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (Exception e){
            e.printStackTrace();
        }
        return CONTINUE;
    }
    return STOP;
}

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如何修复SocketTimeoutException，因为在变量

pageName

下访问生成的URL可以正常工作。因此，我可以假设我的代码没有完全工作。

GAE_PUMP_TIME的值是多少？那么，当您将超时设置为10秒以上时会发生什么？