Java 原因：org.hibernate.QueryException:无法解析属性：last\u name

我有这个代码工作，有我想要的输出

String hql = "FROM Employee ORDER BY last_name";  
Query query = session.createQuery(hql);  
employeeList = query.list();  

我试过这个代码，但失败了

String hql = "FROM Employee E ORDER BY E.last_name";
Query query = session.createQuery(hql);
employeeList = query.list();  

这是个例外

Exception in thread "main" java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee [FROM com.hibernate.exercise6.model.Employee E ORDER BY E.last_name]
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:131)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:155)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:162)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:631)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:101)
at com.hibernate.exercise6.service.EmployeeFunctions.listEmployees(EmployeeFunctions.java:208)
at com.hibernate.exercise6.app.GUIMain.displayListMenu(GUIMain.java:329)
at com.hibernate.exercise6.app.GUIMain.manageRecords(GUIMain.java:140)
at com.hibernate.exercise6.app.GUIMain.main(GUIMain.java:62)
Caused by: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee [FROM com.hibernate.exercise6.model.Employee E ORDER BY E.last_name]
at org.hibernate.QueryException.generateQueryException(QueryException.java:120)
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:218)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:142)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:77)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:152)
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:521)
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:623)
... 5 more
Caused by: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee
at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:62)
at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:56)
at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1801)
at org.hibernate.hql.internal.ast.tree.FromElementType.getPropertyType(FromElementType.java:393)
at org.hibernate.hql.internal.ast.tree.FromElement.getPropertyType(FromElement.java:505)
at org.hibernate.hql.internal.ast.tree.DotNode.getDataType(DotNode.java:660)
at org.hibernate.hql.internal.ast.tree.DotNode.prepareLhs(DotNode.java:264)
at org.hibernate.hql.internal.ast.tree.DotNode.resolve(DotNode.java:204)
at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:109)
at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:104)
at org.hibernate.hql.internal.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:1013)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1286)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExpr(HqlSqlBaseWalker.java:1860)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExprs(HqlSqlBaseWalker.java:1657)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderClause(HqlSqlBaseWalker.java:1630)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:652)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:311)
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:259)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:262)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:190)
... 11 more  

第一个代码和第二个代码的行为不应该相同吗？只介绍了一个别名，对吗

在HQL中，您可以通过实体的属性访问真实的列名。在您的情况下，属性名为

lastName

，列名为

last\u name

。因此，如果使用HQL，则必须使用属性，如果要实现

NativeQuery

，则可以使用列名

您正在对

Employee

实体执行

SELECT

子句，该实体具有

name

属性，最后一个具有

lastName

属性。因此，您的查询必须写为以下内容：

String hql = "FROM Employee E ORDER BY E.name.lastName";  
Query query = session.createQuery(hql);  
employeeList = query.list(); 

在HQL中，您可以通过实体的属性访问真实的列名。在您的情况下，属性名为

lastName

，列名为

last\u name

。因此，如果使用HQL，则必须使用属性，如果要实现

NativeQuery

，则可以使用列名

您正在对

Employee

实体执行

SELECT

子句，该实体具有

name

属性，最后一个具有

lastName

属性。因此，您的查询必须写为以下内容：

String hql = "FROM Employee E ORDER BY E.name.lastName";  
Query query = session.createQuery(hql);  
employeeList = query.list(); 

---

您可以发布

员工

代码吗？您的

员工

课程中没有

姓

。您的HQL中应该是

lastName

。您可以发布

Employee

code吗？您的

Employee

类中没有

last\u name

。在你的HQL中应该是

lastName

。回答得好！我想添加到答案-使用标准API。其保存的查询语言。Hibernate将在没有您的情况下构造查询。它看起来像return createCriteria（Employee.class）.addOrder（Order.asc（“name”））.list（）它实际上应该是

E.name.lastName

，因为

lastName

是

Employee

的组件

name

中的一个字段，谢谢您的好答案！我想添加到答案-使用标准API。其保存的查询语言。Hibernate将在没有您的情况下构造查询。它看起来像return createCriteria（Employee.class）.addOrder（Order.asc（“name”））.list（）它实际上应该是

E.name.lastName

，因为

lastName

是

Employee

的组件

name

中的一个字段，谢谢你的想法

String hql = "FROM Employee E ORDER BY E.name.lastName";  
Query query = session.createQuery(hql);  
employeeList = query.list();