在Java中，将元素分离为整数数组的文件生成的ArrayList转换为整数数组

我对Java中的文件操作非常陌生。我有一个由如下数字组成的文件

六,

1 2

13

我试图把所有这些数字放在一个整数数组中。我找到了一个准备好的代码，将它们放在字符串列表中，但现在它对我来说并不是无用的。我想做的是将它们存储在一个int数组中，并逐个索引地访问它们。我想要int[]NumbersFromFile={6,1,2,1,3}； 这是我的密码

 public String[] ReadNumbersFromFile(String name) throws FileNotFoundException {
    String token1 = "";

    Scanner inFile1 = new Scanner(new File(name)).useDelimiter(",\\s*");

    ArrayList<String> temps = new ArrayList<String>();

    // while loop
    while (inFile1.hasNext()) {
       // find next line
       token1 = inFile1.next();
       temps.add(token1);
    }
    inFile1.close();
    String[] tempsArray = new String[temps.size()];
    tempsArray = temps.toArray(tempsArray);

    for (String s  : tempsArray)
    {
       System.out.print(s);
    }

    return tempsArray;
 }            

如何从该文件获取int数组？ 提前感谢。

更改此行：

ArrayList<String> temps = new ArrayList<String>();

token1 = inFile1.next();

为此：

ArrayList<Integer> temps = new ArrayList<Integer>();

token1 = inFile1.nextInt();

或者，可以编写for循环，使用Integer.parseIntyourInt将ArrayList解析为int[]

---

循环遍历arrayList并添加到和int[]，而不是字符串[]，如下所示：

public int[] ReadNumbersFromFile(String name) throws FileNotFoundException {
    //String to store each number from the file
    String token1 = "";

    //Open the file and create a scanner to read it
    Scanner inFile1 = new Scanner(new File(name));

    //temporary arrayList to store what we read from the file
    //scanners return strings
    ArrayList<String> temps = new ArrayList<String>();

    // while the scanner can see it has more to read
    while (inFile1.hasNext()) {
        // save the number read
        token1 = inFile1.next();

        //add it to the arrayList
        temps.add(token1);
    }

    //close the scanner when done using to free up that resource
    inFile1.close();

    //create the standard int array that is the same length as the arrayList<String>
    int[] tempsArray = new int[temps.size()];

    //loop through the arrayList<String>
    //this is what contains each number from the file, just as Strings
    for(int i = 0; i < temps.size(); i++) {
        //Integar.parseInt(String s) takes a string of numbers and returns it as int
        //save this to our int[]
        tempsArray[i] = Integer.parseInt(temps.get(i));
    }

    //return the int[]
    return tempsArray;
}

---

@frenchDolphin它存储tempsArray[0]处的所有数字，解析不起作用的原因是我尝试了它。我怎么处理这个案子？另一个答案是@B.U frenchDolphin's。试试我的代码，看看它是否有效。我对它进行了编辑，因为您不需要更改分隔符。非常感谢您，它现在可以工作了。你能解释一下背后的逻辑吗@MrMadsen@B.U是的，我编辑了这篇文章，在每一行之前都有一条评论解释它在做什么。如果你还有关于某一行的问题，请告诉我，我会在这里回答。

public int[] ReadNumbersFromFile(String name) throws FileNotFoundException {
    //String to store each number from the file
    String token1 = "";

    //Open the file and create a scanner to read it
    Scanner inFile1 = new Scanner(new File(name));

    //temporary arrayList to store what we read from the file
    //scanners return strings
    ArrayList<String> temps = new ArrayList<String>();

    // while the scanner can see it has more to read
    while (inFile1.hasNext()) {
        // save the number read
        token1 = inFile1.next();

        //add it to the arrayList
        temps.add(token1);
    }

    //close the scanner when done using to free up that resource
    inFile1.close();

    //create the standard int array that is the same length as the arrayList<String>
    int[] tempsArray = new int[temps.size()];

    //loop through the arrayList<String>
    //this is what contains each number from the file, just as Strings
    for(int i = 0; i < temps.size(); i++) {
        //Integar.parseInt(String s) takes a string of numbers and returns it as int
        //save this to our int[]
        tempsArray[i] = Integer.parseInt(temps.get(i));
    }

    //return the int[]
    return tempsArray;
}