Java 如何在不使用集合的情况下按升序打印偶数，降序打印奇数

输入：

10
3 1 45 67 2 56 89 22 11 69

2 22 56 
89 69 67 45 11 3 1

import java.util.Arrays;
import java.util.Scanner;

class T {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Scanner sc = new Scanner(System.in);
        System.out.println("enter a number");
        int n = sc.nextInt();

        int s[] = new int[n];
        for (int i = 0; i < n; i++) {
            int e = sc.nextInt();
            s[i] = e;
        }

        Arrays.sort(s);
        // Even in ascending
        System.out.println("\nEven numbers in ascending order:");
        for (int j = 0; j < n; j++) {

            if (s[j] % 2 == 0) {
                System.out.print(s[j] + " ");
            }
        }

        // Odd in descending
        System.out.println("\nOdd numbers in descending order:");
        for(int j = (n -1); j >= 0; j--) {
            if (s[j] % 2 == 1) {
                System.out.print(s[j] + " ");
            }
        }
    }
}

enter a number
10
3 1 45 67 2 56 89 22 11 69

Even numbers in ascending order:
2 22 56 
Odd numbers in descending order:
89 69 67 45 11 3 1 

输出（我想要的）：

10
3 1 45 67 2 56 89 22 11 69

2 22 56 
89 69 67 45 11 3 1

import java.util.Arrays;
import java.util.Scanner;

class T {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Scanner sc = new Scanner(System.in);
        System.out.println("enter a number");
        int n = sc.nextInt();

        int s[] = new int[n];
        for (int i = 0; i < n; i++) {
            int e = sc.nextInt();
            s[i] = e;
        }

        Arrays.sort(s);
        // Even in ascending
        System.out.println("\nEven numbers in ascending order:");
        for (int j = 0; j < n; j++) {

            if (s[j] % 2 == 0) {
                System.out.print(s[j] + " ");
            }
        }

        // Odd in descending
        System.out.println("\nOdd numbers in descending order:");
        for(int j = (n -1); j >= 0; j--) {
            if (s[j] % 2 == 1) {
                System.out.print(s[j] + " ");
            }
        }
    }
}

enter a number
10
3 1 45 67 2 56 89 22 11 69

Even numbers in ascending order:
2 22 56 
Odd numbers in descending order:
89 69 67 45 11 3 1 

我想按升序打印偶数，降序打印奇数，而不使用集合，因为我不知道集合。在这里，请帮助我如何按降序打印奇数，我可以一直打印到偶数

代码：

导入java.util.array；
导入java.util.Scanner；
T类{
公共静态void main（字符串[]args）{
//TODO自动生成的方法存根
扫描仪sc=新的扫描仪（System.in）；
System.out.println（“输入一个数字”）；
int n=sc.nextInt（）；
int s[]=新的int[n]；
int i；
对于（i=0；i

代码：

10
3 1 45 67 2 56 89 22 11 69

2 22 56 
89 69 67 45 11 3 1

import java.util.Arrays;
import java.util.Scanner;

class T {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Scanner sc = new Scanner(System.in);
        System.out.println("enter a number");
        int n = sc.nextInt();

        int s[] = new int[n];
        for (int i = 0; i < n; i++) {
            int e = sc.nextInt();
            s[i] = e;
        }

        Arrays.sort(s);
        // Even in ascending
        System.out.println("\nEven numbers in ascending order:");
        for (int j = 0; j < n; j++) {

            if (s[j] % 2 == 0) {
                System.out.print(s[j] + " ");
            }
        }

        // Odd in descending
        System.out.println("\nOdd numbers in descending order:");
        for(int j = (n -1); j >= 0; j--) {
            if (s[j] % 2 == 1) {
                System.out.print(s[j] + " ");
            }
        }
    }
}

enter a number
10
3 1 45 67 2 56 89 22 11 69

Even numbers in ascending order:
2 22 56 
Odd numbers in descending order:
89 69 67 45 11 3 1 

说明：

10
3 1 45 67 2 56 89 22 11 69

2 22 56 
89 69 67 45 11 3 1

import java.util.Arrays;
import java.util.Scanner;

class T {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Scanner sc = new Scanner(System.in);
        System.out.println("enter a number");
        int n = sc.nextInt();

        int s[] = new int[n];
        for (int i = 0; i < n; i++) {
            int e = sc.nextInt();
            s[i] = e;
        }

        Arrays.sort(s);
        // Even in ascending
        System.out.println("\nEven numbers in ascending order:");
        for (int j = 0; j < n; j++) {

            if (s[j] % 2 == 0) {
                System.out.print(s[j] + " ");
            }
        }

        // Odd in descending
        System.out.println("\nOdd numbers in descending order:");
        for(int j = (n -1); j >= 0; j--) {
            if (s[j] % 2 == 1) {
                System.out.print(s[j] + " ");
            }
        }
    }
}

enter a number
10
3 1 45 67 2 56 89 22 11 69

Even numbers in ascending order:
2 22 56 
Odd numbers in descending order:
89 69 67 45 11 3 1 

由于数组已排序（按升序），请先打印偶数。

---

然后以相反方向（desc顺序）遍历数组，并打印出奇数。

反向标记并使用相同的for循环打印：

int x = 0;

for (int j = 0; j < n; j++) {

    if (s[j] % 2 == x)
        System.out.println(s[j]);

    if (j == n - 1 && x == 0) {
        x = 1;
        j = 0;
    }
}

intx=0；
对于（int j=0；j