Java长数字太大错误?
为什么我得到的整数太大,而long被分配给min和maxJava长数字太大错误?,java,Java,为什么我得到的整数太大,而long被分配给min和max /* long: The long data type is a 64-bit signed two's complement integer. It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807 (inclusive). Use this data type when y
/*
long: The long data type is a 64-bit signed two's complement integer.
It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807 (inclusive).
Use this data type when you need a range of values wider than those provided by int.
*/
package Literals;
public class Literal_Long {
public static void main(String[] args) {
long a = 1;
long b = 2;
long min = -9223372036854775808;
long max = 9223372036854775807;//Inclusive
System.out.println(a);
System.out.println(b);
System.out.println(a + b);
System.out.println(min);
System.out.println(max);
}
}
java中的所有文字数字默认为
int
,其范围为-2147483648
到2147483647
您的文字超出此范围,因此要进行此编译,您需要指出它们是长
文字(即后缀为L
):
请注意,java同时支持大写L
和小写L
,但我建议不要使用小写L
,因为它看起来像1
:
long min = -9223372036854775808l; // confusing: looks like the last digit is a 1
long max = 9223372036854775807l; // confusing: looks like the last digit is a 1
同样
如果整型文字以ASCII字母L或L(ell)作为后缀,则其类型为long;否则为int型(§4.2.1)
您必须使用
L
向编译器说明它是一个长文本
long min = -9223372036854775808L;
long max = 9223372036854775807L;//Inclusive
你可以用
Long.MIN\u VALUE
和Long.MAX\u VALUE
或1L>>1来装腔作势:你也可以用一个小的l
@OliverWeiler,我想说,要装腔作势,你可以但不应该用一个小的l,因为它看起来像1。如果你用的字体不好,它看起来像1,但当然,为什么要冒混淆的风险呢。
long min = -9223372036854775808L;
long max = 9223372036854775807L;//Inclusive