如何在Appium中从左向右滑动？
由于不推荐使用swipe（），我无法从左向右滑动屏幕。我的应用程序中有4个横幅，我想滑动以查看所有横幅。假设您创建了如何在Appium中从左向右滑动？,appium,appium-android,Appium,Appium Android,由于不推荐使用swipe（），我无法从左向右滑动屏幕。我的应用程序中有4个横幅，我想滑动以查看所有横幅。假设您创建了driver的AndroidDriver实例，您可以向左滑动： // Get location of element you want to swipe WebElement banner = driver.findElement(<your_locator>); Point bannerPoint = banner.getLocation();
driverAndroidDriver // Get location of element you want to swipe
WebElement banner = driver.findElement(<your_locator>);
Point bannerPoint = banner.getLocation();
// Get size of device screen
Dimension screenSize = driver.manage().window().getSize();
// Get start and end coordinates for horizontal swipe
int startX = Math.toIntExact(Math.round(screenSize.getWidth() * 0.8));
int endX = 0;
TouchAction action = new TouchAction(driver);
action
.press(PointOption.point(startX, bannerPoint.getY()))
.waitAction(WaitOptions.waitOptions(Duration.ofMillis(500)))
.moveTo(PointOption.point(endX, bannerPoint.getY()))
.release();
driver.performTouchAction(action);
//获取要滑动的元素的位置
WebElement banner=driver.findElement（）；
Point bannerPoint=banner.getLocation（）；
//获取设备屏幕的大小
维度screenSize=driver.manage（）.window（）.getSize（）；
//获取水平滑动的开始和结束坐标
int startX=Math.toIntExact（Math.round（screenSize.getWidth（）*0.8））；
int-endX=0；
TouchAction动作=新的TouchAction（驱动程序）；
行动
.press（PointOption.point（startX，bannerPoint.getY（）））
.waitAction（WaitOptions.WaitOptions（持续时间500毫秒））
.moveTo（PointOption.point（endX，bannerPoint.getY（）））
.release（）；
驱动程序。执行动作（动作）；
使用最新的Appium 1.8.x服务器这适用于所有方向： 枚举： 实际代码：
public static void swipe(MobileDriver driver, DIRECTION direction, long duration) {
Dimension size = driver.manage().window().getSize();
int startX = 0;
int endX = 0;
int startY = 0;
int endY = 0;
switch (direction) {
case RIGHT:
startY = (int) (size.height / 2);
startX = (int) (size.width * 0.90);
endX = (int) (size.width * 0.05);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(endX, startY)
.release()
.perform();
break;
case LEFT:
startY = (int) (size.height / 2);
startX = (int) (size.width * 0.05);
endX = (int) (size.width * 0.90);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(endX, startY)
.release()
.perform();
break;
case UP:
endY = (int) (size.height * 0.70);
startY = (int) (size.height * 0.30);
startX = (size.width / 2);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(endX, startY)
.release()
.perform();
break;
case DOWN:
startY = (int) (size.height * 0.70);
endY = (int) (size.height * 0.30);
startX = (size.width / 2);
new TouchAction(driver)
.press(startX, startY)
.waitAction(Duration.ofMillis(duration))
.moveTo(startX, endY)
.release()
.perform();
break;
}
}
swipe(driver,DIRECTION.RIGHT);
Dimension size = driver.manage().window().getSize();
System.out.println(size.height+"height");
System.out.println(size.width+"width");
System.out.println(size);
int startPoint = (int) (size.width * 0.99);
int endPoint = (int) (size.width * 0.15);
int ScreenPlace =(int) (size.height*0.40);
int y=(int)size.height*20;
TouchAction ts = new TouchAction(driver);
//for(int i=0;i<=3;i++) {
ts.press(PointOption.point(startPoint,ScreenPlace ))
.waitAction(WaitOptions.waitOptions(Duration.ofMillis(1000)))
.moveTo(PointOption.point(endPoint,ScreenPlace )).release().perform();
Dimension size=driver.manage（）.window（）.getSize（）；
系统输出打印项次（尺寸高度+高度）；
System.out.println（大小.宽度+宽度）；
系统输出打印项次（尺寸）；
int起始点=（int）（size.width*0.99）；
int端点=（int）（size.width*0.15）；
int屏幕位置=（int）（大小、高度*0.40）；
整数y=（整数）大小。高度*20；
TouchAction ts=新的TouchAction（驾驶员）；
//对于（int i=0；i这是针对iOS Mobile的：
//我正在尝试从右向左滑动图像列表
//首先，我获取父元素（表/单元格）id
//然后使用谓词字符串搜索是否存在元素，然后尝试单击
List ele=getMobileElement（ListBtQueicKlink）.findelelements（By.xpath（“.//XguiElementTypeButton”）；
对于（inti=1；i请尝试下面的方法。它适用于Appium 1.16.0版本。
我创建了这个方法，根据屏幕上的特定元素位置向左或向右滑动
元素X：需要在其上执行滑动触摸操作的元素的X坐标。
元素Y：元素的Y坐标。
方向：左/右
//method to left and right swipe on the screen based on coordinates
public void swipeAction(int Xcoordinate, int Ycoordinate, String direction) {
//get device width and height
Dimension dimension = driver.manage().window().getSize();
int deviceHeight = dimension.getHeight();
int deviceWidth = dimension.getWidth();
System.out.println("Height x Width of device is: " + deviceHeight + " x " + deviceWidth);
switch (direction) {
case "Left":
System.out.println("Swipe Right to Left");
//define starting and ending X and Y coordinates
int startX=deviceWidth - Xcoordinate;
int startY=Ycoordinate; // (int) (height * 0.2);
int endX=Xcoordinate;
int endY=Ycoordinate;
//perform swipe from right to left
new TouchAction((AppiumDriver) driver).longPress(PointOption.point(startX, startY)).moveTo(PointOption.point(endX, endY)).release().perform();
break;
case "Right":
System.out.println("Swipe Left to Right");
//define starting X and Y coordinates
startX=Xcoordinate;
startY=Ycoordinate;
endX=deviceWidth - Xcoordinate;
endY=Ycoordinate;
//perform swipe from left to right
new TouchAction((AppiumDriver) driver).longPress(PointOption.point(startX, startY)).moveTo(PointOption.point(endX, endY)).release().perform();
break;
}
}
要获取元素X，Y坐标，请尝试以下方法
int elementX= driver.findElement(elementLocator).getLocation().getX();
int elementY= driver.findElement(elementLocator).getLocation().getY();
使用touchactionsHaven尚未对其进行测试，但看起来上下都不太正确
int elementX= driver.findElement(elementLocator).getLocation().getX();
int elementY= driver.findElement(elementLocator).getLocation().getY();