Java android Studio如何绘制游戏？

我正在尝试创建一个Tic-Tac-Toe游戏。一切正常，如果球员 x或O赢了一条消息显示x或O赢了这场比赛，但问题是当没有赢家时，我应该收到一条消息说“没有赢家，再试一次”。如果你能帮我，你就是我的一天

int activePlayer = 0; // for x player

int[] gameState ={2,2,2,2,2,2,2,2,2}; // 2 means unplayed.

int[][] winningLocation ={{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};
boolean gameover =false;

public void gameLogic(View view){

    ImageView tappedView =(ImageView) view;

    int tappedLocation = Integer.parseInt(view.getTag().toString());

    if(gameState[tappedLocation]==2 && !gameover) {
        gameState[tappedLocation]=activePlayer;

        tappedView.setTranslationY(-3000f);

        if (activePlayer == 0) {

            tappedView.setImageResource(R.drawable.x);

            activePlayer = 1;

        } else if (activePlayer == 1) {
            tappedView.setImageResource(R.drawable.o);
            activePlayer = 0;
        }
        tappedView.animate().translationYBy(3000f).setDuration(500);
    }

    String mesg ="";

    for(int[]winningPostion :winningLocation){

        if(gameState[winningPostion[0]] == gameState [winningPostion[1]]
                && gameState[winningPostion[1]]== gameState [winningPostion[2]]
                && gameState[winningPostion[0]]!=2){

            if (activePlayer ==0)

                mesg = "O is the winner!";

            if(activePlayer==1)

                mesg = "X is the winner!";

            else if(activePlayer==2)

                mesg="there is no winner";





            LinearLayout winnerLayout =(LinearLayout)findViewById (R.id.winnerLayout);
            winnerLayout.setVisibility(View .VISIBLE);

            TextView winnermesg = (TextView) findViewById(R.id.editText);
            winnermesg.setText(mesg);

            gameover=true;
        }
    }




}

// a method that let the players play again

public void playagain(View view){
    LinearLayout winnerLayout = (LinearLayout) findViewById(R.id.winnerLayout);
    winnerLayout.setVisibility(View.INVISIBLE);
    gameover=false;
    activePlayer=0;

    for (int i =0; i < gameState.length;i++)
        gameState[i]=2;

    GridLayout gridlayout = (GridLayout) findViewById(R.id.gridlayout);
    for(int i =0 ; i < gridlayout.getChildCount(); i++)
        ((ImageView)gridlayout.getChildAt(i)).setImageResource(0);
}












@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);







 // to play the song
      mediaPlayer = MediaPlayer.create(getApplicationContext(),R.raw.song);
      mediaPlayer.start();


    Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
    setSupportActionBar(toolbar);

    // to show and hide the playing again button

   LinearLayout winnerLayout = ( LinearLayout) findViewById(R.id.winnerLayout);
    winnerLayout.setVisibility(View.INVISIBLE);





   FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
    fab.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
                    .setAction("Action", null).show();
        }
    });
}





@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.menu_main, menu);
    return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // Handle action bar item clicks here. The action bar will
    // automatically handle clicks on the Home/Up button, so long
    // as you specify a parent activity in AndroidManifest.xml.
    int id = item.getItemId();

    //noinspection SimplifiableIfStatement
    if (id == R.id.action_settings) {
        return true;
    }

    return super.onOptionsItemSelected(item);
}

int-activePlayer=0；//对于x播放器
int[]游戏状态={2,2,2,2,2,2,2,2}；//2表示未播放。
int[]winningLocation={0,1,2}，{3,4,5}，{6,7,8}，{0,3,6}，{1,4,7}，{2,5,8}，{0,4,8}，{2,4,6}；
布尔gameover=false；
公共void游戏逻辑（视图）{
ImageView tappedView=（ImageView）视图；
int-tappedLocation=Integer.parseInt（view.getTag（）.toString（））；
如果（游戏状态[tappedLocation]==2&&！游戏结束）{
游戏状态[tappedLocation]=活动玩家；
tappedView.setTranslationY（-3000f）；
如果（activePlayer==0）{
tappedView.setImageResource（R.drawable.x）；
activePlayer=1；
}else if（activePlayer==1）{
tappedView.setImageResource（R.drawable.o）；
activePlayer=0；
}
tappedView.animate（）.translationBy（3000f）.setDuration（500）；
}
字符串mesg=“”；
对于（int[]WinningPosition:winningLocation）{
如果（游戏状态[winningPostion[0]]==游戏状态[winningPostion[1]]
&&游戏状态[winningPostion[1]]==游戏状态[winningPostion[2]]
&&游戏状态[winningPostion[0]！=2）{
如果（activePlayer==0）
mesg=“O是赢家！”；
如果（activePlayer==1）
mesg=“X是赢家！”；
else if（activePlayer==2）
mesg=“没有赢家”；
LinearLayout winnerLayout=（LinearLayout）findViewById（R.id.winnerLayout）；
winnerLayout.setVisibility（View.VISIBLE）；
TextView Winnermasg=（TextView）findViewById（R.id.editText）；
winnermesg.setText（mesg）；
gameover=true；
}
}
}
//一种让玩家再次玩的方法
再次播放公共void（视图）{
LinearLayout winnerLayout=（LinearLayout）findViewById（R.id.winnerLayout）；
winnerLayout.setVisibility（视图.不可见）；
gameover=false；
activePlayer=0；
对于（inti=0；i

我想你还没有学会如何调试你的应用程序，否则你可以一步一步地调试代码，准确地知道变量值是什么，并找出错误所在。感谢你抽出时间给我回信，我确实使用了调试，但我不太明白我真的很坚持，我对android studio很陌生。