Java String.split（）工作不正常，扫描仪读取不正确，出现问题

我不知道为什么split命令对我不起作用，sc.nextLine；命令也没有正确读取我的输入，程序正在输出以下内容：

Menu:
1 - Sign up on service.

这是我的键盘输入

1

程序输出：

Input a single line separated by COMMA and NO SPACES, the software will validade your entry.
1 - Your First Name, 2 - Your Second Name, 3 - Your Age, 4 - Your Gender 
(F or M in UPPER CASE) 5 - Your Email, 6 - Your Password:

我的第二个输入：

Vanessa,Jhonson,25, M,aaa@aol.com,111222

现在，在输入之后输出。这是for循环打印字符串数组k[]的输出，与应该的值不接近，不知道为什么

[Ljava.lang.String;@55f96302 
Wrong input pattern, try again. //this is the output if the string s doesn't match the regex


Menu: //Program looping (expected)
1 - Sign up on service.

下面的代码是我的源代码，它有这个主方法和另一个类中的另一个方法，在这个类之后你会很好

package view;

import java.util.Scanner;
import control.RegistrationController;

public class ClientFacade {
    public static Scanner sc = new Scanner(System.in);

    public static void main(String[] args) {
        boolean exit = false;
        int option = 0;
        RegistrationController rc = new RegistrationController();

        while(exit == false){
            System.out.println("Menu:");
            System.out.println("1 - Sign up on service.");

            option = sc.nextInt(); //ERROR AT THIS LINE

            switch(option){

            case 0:{
                exit = true;
                break;
            }
            case 1:{
                rc.userSignUp();
                break;
            }
            default:{
                System.out.println("Invalid option.");
                break;
            }
            }
        }
        sc.close();
    }
}

下面的代码是这个程序中的一个方法。 包装控制

import java.util.Scanner;
import java.util.regex.Pattern;

import view.ClientFacade;
import model.Person;
import model.Server;

public class RegistrationController {

public void userSignUp(){
    Scanner sc = new Scanner(System.in);
    User usr = new User();
    RegistrationController rc = new RegistrationController();
    String regex = "$(\\w)+(\\,)(\\w)+(\\,)(\\d){2,3}(\\,)[F,M](\\,)(\\w)+(@)(\\w)+(.)(\\w)+((.)(\\w)+)?(,)(\\w)+^";
    System.out.println("Input a single line separated by COMMA and NO SPACES, "
            + "the software will validade your entry.\n"
            + "1 - Your First Name, 2 - Your Second Name, "
            + "3 - Your Age, 4 - Your Gender \n(F or M in UPPER CASE) "
            + "5 - Your Email, 6 - Your Password:\n");

    String s = sc.nextLine();               //BUG, NOT ABLE TO READ A PROPER STRING
    s = s.trim();
    String [] k = s.split("(\\,)");         //THIS IS ABSOLUTELY NOT WORKING FOR NO REASON

    System.out.println(s);                  //DEBUGGING LINE
    for (int i = 0; i < k.length; i++) {    //DEBUGGING BLOCK
        String string = k[i];
        System.out.println(k);
    }


    if (Pattern.matches(regex, s)){
        usr.setAdmLevel(0);
        usr.setName(k[0]+" "+k[1]);
        usr.setAge(Integer.parseInt(k[2]));
        usr.setGender(k[3]);
        usr.setEmail(k[4]);
        usr.setPassword(k[5]);
        if (rc.registerUser(usr) != 0){
            System.out.println("Your are signed up! Your ID: "+usr.getId());
        }else {
            System.out.println("A problem ocurred, not registered.");
        }
    }else{
        System.out.println("Wrong input pattern, try again.");
    }
}
}

---

解决了，正则表达式正则表达式的起始和终止被反转，当它应该是^$时是$^，我还发现s.trimm；对于带有逗号的完整字符串不起作用，所以我在拆分字符串后在每个块的内部对其进行了修剪

for (int i = 0; i < k.length; i++) {    //TRIMMING BLOCK
            k[i] = k[i].trim();
            System.out.println(k[i]);
        }

---

在s.split中不需要\\\\`System.out.printlnk；应该是System.out.printlnk[i]。你在一个数组上调用toString——这从来都不是一个好主意……而且你的正则表达式模式也不符合你的输入。你的输入中还有一个空格，M，它不符合你自己的指令。这一行：s=s.trim；应该消除@user2696372上的空格，但是没有