Java 初始化对象数组成功后,应用程序崩溃
我想从字符串数组初始化对象数组 我有一个数组,它有6条字符串记录,我想初始化两个具有相同字符串记录的对象,这意味着在数组中,对象将有12条记录 出于某种原因,我设法实例化了对象数组,但在循环结束后,应用程序崩溃了Java 初始化对象数组成功后,应用程序崩溃,java,android,arrays,Java,Android,Arrays,我想从字符串数组初始化对象数组 我有一个数组,它有6条字符串记录,我想初始化两个具有相同字符串记录的对象,这意味着在数组中,对象将有12条记录 出于某种原因,我设法实例化了对象数组,但在循环结束后,应用程序崩溃了 public class Card { private String pic; public Card(String pic) { this.pic = pic; } public String getPic() {
public class Card {
private String pic;
public Card(String pic) {
this.pic = pic;
}
public String getPic() {
return pic;
}
public void setPic(String pic) {
this.pic = pic;
}
@Override
public String toString() {
return "Card{" +
"pic='" + pic + '\'' +
'}';
}
}
2020-05-27 17:36:37.345 358-358/? I/case: crocodile 0
2020-05-27 17:36:37.345 358-358/? I/case: crocodile 1
2020-05-27 17:36:37.345 358-358/? I/case: duck 2
2020-05-27 17:36:37.345 358-358/? I/case: duck 3
2020-05-27 17:36:37.345 358-358/? I/case: lizard 4
2020-05-27 17:36:37.345 358-358/? I/case: lizard 5
2020-05-27 17:36:37.345 358-358/? I/case: mosqitue 6
2020-05-27 17:36:37.345 358-358/? I/case: mosqitue 7
2020-05-27 17:36:37.345 358-358/? I/case: parrot 8
2020-05-27 17:36:37.345 358-358/? I/case: parrot 9
2020-05-27 17:36:37.345 358-358/? I/case: zebra 10
2020-05-27 17:36:37.345 358-358/? I/case: zebra 11
卡片档案结束
package com.example.memorygame;
import androidx.appcompat.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
public class MainActivity extends AppCompatActivity {
private void main() {
String[] pictures = {"crocodile", "duck", "lizard", "mosqitue", "parrot", "zebra"};
//String[] pictures = {"crocodile", "crocodile", "duck","duck", "lizard","lizard", "mosqitue","mosqitue", "parrot","parrot", "zebra" ,"zebra"};
Card[] cards = new Card[pictures.length*2];
Functions functions = new Functions();
for (int i = 0; i < cards.length*2; i+=2) {
cards[i] = new Card(pictures[i/2]);
cards[i + 1] = new Card(pictures[i/2]);
Log.i("case", cards[i].getPic()+" "+String.valueOf(i));
Log.i("case", cards[i].getPic()+" "+String.valueOf(i+1));
}
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
main();
}
}
这些日志之后我没有任何内容,我也找不到应用程序崩溃的任何原因。您正在迭代I
ArrayIndexOutOfBoundsException
,而条件应该是I
。尝试在循环中更改以下条件,它应该可以正常工作
public class Card {
private String pic;
public Card(String pic) {
this.pic = pic;
}
public String getPic() {
return pic;
}
public void setPic(String pic) {
this.pic = pic;
}
@Override
public String toString() {
return "Card{" +
"pic='" + pic + '\'' +
'}';
}
}
2020-05-27 17:36:37.345 358-358/? I/case: crocodile 0
2020-05-27 17:36:37.345 358-358/? I/case: crocodile 1
2020-05-27 17:36:37.345 358-358/? I/case: duck 2
2020-05-27 17:36:37.345 358-358/? I/case: duck 3
2020-05-27 17:36:37.345 358-358/? I/case: lizard 4
2020-05-27 17:36:37.345 358-358/? I/case: lizard 5
2020-05-27 17:36:37.345 358-358/? I/case: mosqitue 6
2020-05-27 17:36:37.345 358-358/? I/case: mosqitue 7
2020-05-27 17:36:37.345 358-358/? I/case: parrot 8
2020-05-27 17:36:37.345 358-358/? I/case: parrot 9
2020-05-27 17:36:37.345 358-358/? I/case: zebra 10
2020-05-27 17:36:37.345 358-358/? I/case: zebra 11
for (int i = 0; i < pictures.length; i++) {
cards[2*i] = new Card(pictures[i]);
cards[2*i + 1] = new Card(pictures[i]);
Log.i("case", cards[2*i].getPic()+" "+String.valueOf(i));
Log.i("case", cards[2*i+1].getPic()+" "+String.valueOf(i+1));
}
for(int i=0;i
另外,请确保您的logcat具有在应用程序崩溃时能够看到异常的配置。您正在迭代i
ArrayIndexOutOfBoundsException
,而条件应该是i
。尝试在循环中更改以下条件,它应该可以正常工作
for (int i = 0; i < pictures.length; i++) {
cards[2*i] = new Card(pictures[i]);
cards[2*i + 1] = new Card(pictures[i]);
Log.i("case", cards[2*i].getPic()+" "+String.valueOf(i));
Log.i("case", cards[2*i+1].getPic()+" "+String.valueOf(i+1));
}
for(int i=0;i
此外,请确保您的logcat具有在应用程序崩溃时能够看到异常的配置。您使用错误的长度进行迭代,这导致IndexOutOfBoundsException,因此应用程序正在崩溃
for (int i = 0; i < cards.length; i+=2) {
cards[i] = new Card(pictures[i/2]);
cards[i + 1] = new Card(pictures[i/2]);
Log.i("case", cards[i].getPic()+" "+String.valueOf(i));
Log.i("case", cards[i+1].getPic()+" "+String.valueOf(i+1));
}
for(int i=0;i
同样在上一个日志中,我在打印卡片[i]的值,它给出了相同的值,但它是错误的,它只打印了0,2,4,6,8,10的值。
它应该打印0,1,2,3,4,5,6,7,8,9,10,11的值。您使用错误的长度进行迭代,导致IndexOutOfBoundsException,因此应用程序正在崩溃
for (int i = 0; i < cards.length; i+=2) {
cards[i] = new Card(pictures[i/2]);
cards[i + 1] = new Card(pictures[i/2]);
Log.i("case", cards[i].getPic()+" "+String.valueOf(i));
Log.i("case", cards[i+1].getPic()+" "+String.valueOf(i+1));
}
for(int i=0;i
同样在上一个日志中,我在打印卡片[i]的值,它给出了相同的值,但它是错误的,它只打印了0,2,4,6,8,10的值。
它应该打印0,1,2,3,4,5,6,7,8,9,10,11的值。一旦进入i的范围,即实际数组大小的两倍,您认为会发生什么?你不是得到一个数组索引越界异常吗?请阅读有关调试代码的提示。你认为一旦进入i的范围,即实际数组大小的两倍,会发生什么情况?你没有得到数组索引越界异常吗?请阅读有关调试代码的提示。我觉得
I
比I+=2更可读,然后使用I/2获得picture@SairajSawant,是的,它更可读,但问题是我们要在card中添加值,所以最好使用cards.length进行迭代,虽然他的要求都是正确的。我觉得I
比I+=2更可读,然后用I/2来获得picture@SairajSawant,是的,它更可读,但问题是我们要在card中添加值,所以最好使用cards.length进行迭代,尽管在他的要求中,这两项都是正确的。这将只生成12个更新答案中的7条记录。这将只生成12个更新答案中的7条记录。