Java 为什么我的编辑文本没有过滤listview

我正在尝试筛选从数据库填充的listview。 这是我的活动代码

listView = (ListView) findViewById(R.id.list1);
    listView.setTextFilterEnabled(true);
    myAdapter = new MyAdapter(SearchActivity.this, R.layout.list_items_layout);
    listView.setAdapter(myAdapter);

    list = new ArrayList<>();

    mDBHelper = new DatabaseHelper(SearchActivity.this);
    sqLiteDatabase = mDBHelper.getReadableDatabase();
    cursor =  mDBHelper.getAll(sqLiteDatabase);

    if(cursor.moveToFirst()){
        do{
            String id, name, email, contact, fav, cat, audio, count;
            id = cursor.getString(0);
            name = cursor.getString(1);
            email = cursor.getString(2);
            contact = cursor.getString(3);
            fav = cursor.getString(4);
            cat = cursor.getString(5);
            audio = cursor.getString(6);
            count = cursor.getString(7);

            Person person = new Person(id,name,email,contact,fav,cat, audio, count);
            myAdapter.add(person);
            list.add(person);
        } while (cursor.moveToNext());
    }

    listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

                Person person = list.get(position);

                Intent intent = new Intent(SearchActivity.this, ReceiveDataActivity.class);

                intent.putExtra("KEY_ID", person.getId());
                intent.putExtra("NAME", person.getName());
                intent.putExtra("EMAIL", person.getEmail());
                intent.putExtra("CONTACT", person.getContact());
                intent.putExtra("FAVORITE", person.getFav());
                intent.putExtra("AUDIO", person.getAudio());
                intent.putExtra("COUNT", person.getCount());

                startActivity(intent);
            }
        });


    SearchButton=(Button)findViewById(R.id.searchButton);

    searchName=(EditText)findViewById(R.id.editText);
    searchName.addTextChangedListener(new TextWatcher() {

            @Override
            public void onTextChanged(CharSequence arg0, int arg1, int arg2, int arg3) {
                // TODO Auto-generated method stub
                SearchActivity.this.myAdapter.getFilter().filter(arg0);
                myAdapter.notifyDataSetChanged();
            }

            @Override
            public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
                                          int arg3) {
                // TODO Auto-generated method stub

            }

            @Override
            public void afterTextChanged(Editable arg0) {
                // TODO Auto-generated method stub

            }
        });

当我在编辑文本中键入单词时，listview不会过滤

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附言：我对Android编程（java）非常陌生。我可能不理解这个解释，但如果有任何帮助，我将不胜感激。

为适配器使用默认过滤器有点麻烦，因为您需要创建一个内部类，并重写几个方法。在适配器中实现以下方法更容易、可读性更强：

public void filter(String charText) {
        list.clear();    // clear list
        charText = charText.toLowerCase();
        if (charText.length() == 0) {
            list.addAll(people);  // restore original list if no filter is applied
        } else {
            for (Object item : people) {
                Person person = (Person) item;
                if (person.getName().toLowerCase().contains(charText)) {
                    list.add(person);   // add item to filtered list if contains string
                }
            }
        }
        notifyDataSetChanged();
    }

您还应该在适配器中创建第二个arrayList来存储原始项的副本，并创建一个方法来初始化它：

 private List people = new ArrayList();


 public void initPeople() {
      people.addAll(list);  // copies original list to people list
 }

从数据库填充列表后，应该初始化人员数组 通过调用myAdapter.initPeople（）；在搜索活动中

最后，在SearchActivity中，替换SearchActivity.this.myAdapter.getFilter（）.filter（arg0）；与

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我确实看到您试图从UI线程上的DB加载数据，这会使您的应用程序变得迟钝，触发ANR，等等on@EpicPandaForce有什么简单的方法可以做到这一点吗？很有魅力。

 private List people = new ArrayList();


 public void initPeople() {
      people.addAll(list);  // copies original list to people list
 }

SearchActivity.this.myAdapter.filter(arg0.toString());