在Java中，使用其他方法中的参数调用方法

我脑子里有一个可能的解决方案，但我不太知道如何用代码来解决这个问题。我在Java的方法中调用方法时遇到了麻烦

我有以下代码：

public Student getStudent(String queryWord){
    //the queryWord here should actually be the String result that returnQueryColumn returns

}

private static Map<String, String> returnMap(String myQuery){
    String[] params = myQuery.split("=");
    Map<String, String> myMap = new HashMap<String, String>();
    String myKey = params[0];
    String myValue = params[1];

    //myKey should be for example firstName, myValue should be the ACTUAL first name of the student
    myMap.put(myKey,myValue);

    return myMap;
}

private static String returnQueryColumn(Map<String, String> myMap){
    //here I want to get just the KEY from the myMap(from the returnMap method)
    //that key should be the column in my database, so I need this so that later on I can compare if the given key (firstName) is present in the database as a column

    String queryWord = returnMap().get(); //query should get firstName in my case

    return queryWord;
}

我知道这个代码不起作用，但我需要一些帮助，我如何才能实现我的想法？我被困在这个问题上-我如何在其他方法中调用一个方法，并使第一个方法中返回的字符串成为第二个方法中的参数。

假设您有学生类：

如果我理解你的意图是正确的，主类可以是这样的

示例代码打印学生全名属性

public class Main {

    public static void main(String[] args) {
        Student student = getStudent("john=John Appleseed");
        System.out.println(student.fullName);
    }

    public static Student getStudent(String myQuery) {
        return returnQueryColumn(myQuery);
    }

    private static Map<String, Student> returnMap(String myQuery){
        String[] params = myQuery.split("=");
        Map<String, Student> myMap = new HashMap<String, Student>();
        String myKey = params[0];
        String myValue = params[1];
        Student student = new Student(myValue);
        myMap.put(myKey, student);

        return myMap;
    }

    private static Student returnQueryColumn(String myQuery) {
        String[] params = myQuery.split("=");
        String key = params[0];
        return returnMap(myQuery).get(key);
    }
}

---

调用方法并传递参数？你还不明白什么？我仍然不知道你到底想要实现什么，但你说你有想法，但你不知道如何做到这一点——这在我看来是一个挑战。。。你的投入是什么，你的预期产出是什么？

public class Main {

    public static void main(String[] args) {
        Student student = getStudent("john=John Appleseed");
        System.out.println(student.fullName);
    }

    public static Student getStudent(String myQuery) {
        return returnQueryColumn(myQuery);
    }

    private static Map<String, Student> returnMap(String myQuery){
        String[] params = myQuery.split("=");
        Map<String, Student> myMap = new HashMap<String, Student>();
        String myKey = params[0];
        String myValue = params[1];
        Student student = new Student(myValue);
        myMap.put(myKey, student);

        return myMap;
    }

    private static Student returnQueryColumn(String myQuery) {
        String[] params = myQuery.split("=");
        String key = params[0];
        return returnMap(myQuery).get(key);
    }
}