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Java 插入mysql不起作用_Java_Mysql - Fatal编程技术网

Java 插入mysql不起作用

Java 插入mysql不起作用,java,mysql,Java,Mysql,这是我的代码,我不知道,但它不会插入到我的数据库中您没有为stat3/sqlbebe提供两个参数 此外,将所有内容包装在带有空catch的try块中也无济于事,这会导致任何异常都被默默地忽略。打印/记录/重试错误,您将看到SQL语句失败的原因。始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终关闭最后块中的连接 try { Class.forName("com.mysql.jdbc.Driver"); Connection dbaTo = D

这是我的代码,我不知道,但它不会插入到我的数据库中

您没有为
stat3
/
sqlbebe
提供两个参数


此外,将所有内容包装在带有空catch的try块中也无济于事,这会导致任何异常都被默默地忽略。打印/记录/重试错误,您将看到SQL语句失败的原因。

始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终、始终关闭
最后
块中的
连接
try {
    Class.forName("com.mysql.jdbc.Driver");
    Connection dbaTo = DriverManager.getConnection("jdbc:mysql://localhost:3306/ourDB1", "root", "");

    PreparedStatement stat2 = dbaTo.prepareStatement("SELECT * FROM tblEntry");
    journEnt = journCombo.getSelectedItem().toString();

    String sqlbebe = "INSERT INTO tblJournEnt(strEntJournCode, strEntJournType) VALUES (?, ?)";
    PreparedStatement stat3 = dbaTo.prepareStatement(sqlbebe);
    ResultSet resultaNgSet = stat2.executeQuery();

    if(resultaNgSet.next()) {
    do{ 
        kuhaEntCode = resultaNgSet.getString(1);    
        substring2 = kuhaEntCode.substring(Math.max(kuhaEntCode.length() - 3, 0));

    }while(resultaNgSet.next());
        } //IF////////////////////////////////////////////////////////////

    else{
        stringsaEnt = "Ent000";         
    }

    int convertToInt2 = Integer.parseInt(substring2);
    int addition2 = convertToInt2 + 1;

    if (addition2 >= 10) {
        String prd = "ent0"; 
        stringsaEnt = prd + addition2;
    }
    else {
        String prd2 = "ent00";
        stringsaEnt = prd2 + addition2; 
        //pasaEnt(stringsaEnt);

    }



    stat3.setString(1, stringsaEnt);
    stat3.setString(2, journEnt);
    stat3.addBatch();
    stat3.executeBatch();
    stat3.close();

}catch(Exception saiko) {

}