Java 交替使用PipedOutStream PipedInputStream编号示例
我想使用Java 交替使用PipedOutStream PipedInputStream编号示例,java,multithreading,inputstream,outputstream,producer-consumer,Java,Multithreading,Inputstream,Outputstream,Producer Consumer,我想使用PipedOutputStream和PipedInputStreamJava类编写类似于生产者消费者问题的示例 注:这是应用其原理的小示例 public static void main(String[] args) { try { final PipedOutputStream pipedSrc = new PipedOutputStream(); final PipedInputStream pipedSnk = new PipedInputStream();
PipedOutputStream
和PipedInputStream
Java类编写类似于生产者消费者问题的示例
注:这是应用其原理的小示例
public static void main(String[] args) {
try {
final PipedOutputStream pipedSrc = new PipedOutputStream();
final PipedInputStream pipedSnk = new PipedInputStream();
pipedSnk.connect(pipedSrc);
int putNumbers = ThreadLocalRandom.current().nextInt(5, 10);
Runnable runnableGet = () -> {
int getNumbers = getNumbers(pipedSnk);
System.out.println("Read " + getNumbers + " numbers from the PipedInputStream");
};
Thread threadGet = new Thread(runnableGet, "threadGet");
threadGet.start();
Runnable runnablePut = () -> {
System.out.println("Write: " + putNumbers + " numbers to the PipedOutputStream");
putNumbers(pipedSrc, putNumbers);
};
Thread threadPut = new Thread(runnablePut, "threadPut");
threadPut.start();
} catch (IOException e) { /*Ignored Now*/}
}
现在的方法是:
public static void putNumbers(PipedOutputStream pipedSrc, int numbers) {
try {
for (int i = 0; i < numbers; i++) {
Integer number = ThreadLocalRandom.current().nextInt(0, 100);
System.out.println("Put number: " + number);
pipedSrc.write(number.toString().getBytes());
try {
int timeSleeping = ThreadLocalRandom.current().nextInt(500, 1000);//Simulate some duration
Thread.sleep(timeSleeping);
} catch (InterruptedException ex) {
System.out.println(ex.toString());
}
}
pipedSrc.flush();
pipedSrc.close();
} catch (IOException e) { /*Ignored Now*/}
}
public static int getNumbers(PipedInputStream pipedSnk) {
int numbers = 0;
try {
byte[] readBytes = new byte[8];
int qtyBytes;
while ((qtyBytes = pipedSnk.read(readBytes)) != -1) {
numbers++;
byte[] bytesNumber = new byte[qtyBytes];
System.arraycopy(readBytes, 0, bytesNumber, 0, qtyBytes);
System.out.println("Get Number: " + new String(bytesNumber));
}
} catch (IOException e) { /*Ignored Now*/}
return numbers;
}
更改源代码
public static void putNumbers(PipedOutputStream pipedSrc, int numbers) {
try {
DataOutputStream dos = new DataOutputStream(new BufferedOutputStream(pipedSrc));
for (int i = 0; i < numbers; i++) {
Integer number = ThreadLocalRandom.current().nextInt(0, 100);
System.out.println("Put number: " + number);
dos.writeInt(number);
try {
int timeSleeping = ThreadLocalRandom.current().nextInt(500, 1000);//Simulate some duration
Thread.sleep(timeSleeping);
} catch (InterruptedException ex) {
System.out.println(ex.toString());
}
}
dos.flush();
dos.close();
} catch (IOException e) { /*Ignored Now*/}
}
public static int getNumbers(PipedInputStream pipedSnk) {
int numbers = 0;
try {
DataInputStream dis = new DataInputStream(new BufferedInputStream(pipedSnk));
Boolean end = false;
while (!end) {
try {
Integer number = dis.readInt();
System.out.println("Get Number: " + number);
numbers++;
} catch (EOFException e) {
end = true;
}
}
} catch (IOException e) { /*Ignored Now*/}
return numbers;
}
如何使用PipedInputStream
和PipedOutputStream
交错和分离生成的数字?只需在每次迭代后调用dos.flush()
这是因为您的DataOutputStream
具有BufferedOutputStream
,因此它在写入您的PipedOutputStream
输出流之前会进行缓冲。如果您希望总是在不缓冲的情况下立即写入,请在每个dos.writeInt()
语句之后调用dos.flush()
,或者不使用缓冲流
因此,我的putNumbers
如下所示:
public static void putNumbers(PipedOutputStream pipedSrc, int numbers) {
try {
DataOutputStream dos = new DataOutputStream(pipedSrc);
for (int i = 0; i < numbers; i++) {
Integer number = ThreadLocalRandom.current().nextInt(0, 100);
System.out.println("Put number: " + number);
dos.writeInt(number);
try {
int timeSleeping = ThreadLocalRandom.current().nextInt(500, 1000);//Simulate some duration
Thread.sleep(timeSleeping);
} catch (InterruptedException ex) {
System.out.println(ex.toString());
}
dos.flush(); //<--changed
}
dos.close();
} catch (IOException e) { /*Ignored Now*/}
}
publicstaticvoidputnumbers(PipedOutputStream pipedSrc,int-numbers){
试一试{
DataOutputStream dos=新的DataOutputStream(pipedSrc);
对于(int i=0;i dos.flush();//谢谢,是阻塞吗?@ChepeQuestn是的,消费者将阻塞,直到有东西要读,生产者将阻塞,以防流缓冲区完全填满
$ java -cp /.../Java/classes PipedNumbers
Write: 7 numbers to the PipedOutputStream
Put number: 17
Put number: 70
Put number: 88
Put number: 12
Put number: 60
Put number: 19
Put number: 41
Get Number: 17
Get Number: 70
Get Number: 88
Get Number: 12
Get Number: 60
Get Number: 19
Get Number: 41
Read 7 numbers from the PipedInputStream
$
public static void putNumbers(PipedOutputStream pipedSrc, int numbers) {
try {
DataOutputStream dos = new DataOutputStream(pipedSrc);
for (int i = 0; i < numbers; i++) {
Integer number = ThreadLocalRandom.current().nextInt(0, 100);
System.out.println("Put number: " + number);
dos.writeInt(number);
try {
int timeSleeping = ThreadLocalRandom.current().nextInt(500, 1000);//Simulate some duration
Thread.sleep(timeSleeping);
} catch (InterruptedException ex) {
System.out.println(ex.toString());
}
dos.flush(); //<--changed
}
dos.close();
} catch (IOException e) { /*Ignored Now*/}
}
public static void putNumbers(PipedOutputStream pipedSrc, int numbers) {
try {
byte[] writeBytes;
for (int i = 0; i < numbers; i++) {
Integer number = ThreadLocalRandom.current().nextInt(0, 1000);
System.out.println("Put number: " + number);
byte[] bytesNumber = number.toString().getBytes();
writeBytes = new byte[8];
System.arraycopy(bytesNumber, 0, writeBytes, 0, bytesNumber.length);
pipedSrc.write(writeBytes);
try {
int timeSleeping = ThreadLocalRandom.current().nextInt(500, 1000);//Simulate some duration
Thread.sleep(timeSleeping);
} catch (InterruptedException ex) {
System.out.println(ex.toString());
}
}
pipedSrc.flush();
pipedSrc.close();
} catch (IOException e) { /*Ignored Now*/}
}
Write: 8 numbers to the PipedOutputStream
Put number: 25
Put number: 57
Get Number: 25
Get Number: 57
Put number: 37
Get Number: 37
Put number: 31
Get Number: 31
Put number: 36
Put number: 10
Get Number: 36
Get Number: 10
Put number: 86
Get Number: 86
Put number: 59
Get Number: 59
Read 8 numbers from the PipedInputStream