Java 在SDK 2.2以上，HTTP Post从不响应（冻结）

所以我已经在安卓应用上工作了一段时间了。一切都很顺利，直到我在安卓2.2以上的设备上测试了这段代码

我只是在一个异步任务中将数据发布到我的PHP服务器上，它永远不会完成，没有错误，什么都没有。我试图设置超时，但没有成功。我在try{}catch{}块中放入了每一条不同的语句，但没有一条语句触发。通过在互联网上阅读，该bug似乎位于HTTPClient.execute（httppost）序列的某个地方。这是我的密码：

private class NewUserTask extends AsyncTask<Context, Void, String> {

    @Override
    protected String doInBackground(Context... params) {

        Functions functions = new Functions();
        if (!functions.isOnline(params[0])) {
            return "false";
        }

        String result = null;
        InputStream is = null;
        StringBuilder sb = null;

        String userDeviceID = Secure.getString(params[0].getContentResolver(),Secure.ANDROID_ID);
        String userAccount = getUsername(params[0]);

        HttpClient httpclient = null;
        try {
            HttpParams httpParameters = new BasicHttpParams();
            HttpConnectionParams.setConnectionTimeout(httpParameters, 3000);
            HttpConnectionParams.setSoTimeout(httpParameters, 5000);

            httpclient = new DefaultHttpClient(httpParameters);
        }catch (Exception e) {
            return "error httpclient setup";
        }

        String url = null;
        try {
            url = "http://www.xxx.com/xxx/xxx.php?userDeviceID=" + userDeviceID + "&database=" + "xxx" + "&userAccount=" + userAccount;
        }catch (Exception e) {
            return "url setup";
        }


        HttpPost httppost = null;
        try {
            httppost = new HttpPost(url);
        }catch (Exception e) {
            return "httppostsetup";
        }

        try {
            httppost.setEntity(new UrlEncodedFormEntity(new ArrayList()));
        }catch (Exception e) {
            return "setetnityfsda";
        }

        HttpResponse response = null;
        try {
            response = httpclient.execute(httppost);
        }catch (Exception e) {
            return "response";
        }

        try {
            is = response.getEntity().getContent();
        }catch (Exception e) {
            return "getcontent";
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"));
            sb = new StringBuilder();
            sb.append(reader.readLine() + "\n");
            String line = "0";

            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }

            is.close();
            String temp = sb.toString();
            temp = temp.substring(0, temp.length() - 1);
            result = temp;

        }catch (Exception e) {
            return "error in reader";
        }

        return result;
    }


    protected void onPostExecute(String result) {
        Functions functions = new Functions();

        functions.showMessage("Info", result, DisplayExtrasActivity.this);
    }

    private String getUsername(Context context){
        Pattern emailPattern = Patterns.EMAIL_ADDRESS; // API level 8+
        Account[] accounts = AccountManager.get(context).getAccounts();
        for (Account account : accounts) {
            if (emailPattern.matcher(account.name).matches()) {
                return account.name;
            }
        }

        return null;
    }
}

我真的希望有人能帮助我，因为我几乎绝望了。我花了一个又一个小时在这些问题上，试图找出我错在哪里

编辑：

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更多代码

为什么您没有使用2.2以上的设备进行测试？我们已经进入2014年了！您能发布logcat错误吗？您能同时显示

AsyncTask

的完整代码吗？创建任务后，您是否执行了该任务？

new NewUserTask().execute(DisplayExtrasActivity.this);