Java 如何获取zip文件中所有目录的列表

我有一个zip文件，其目录结构如下：

file.zip
       - dir1
          - dir1_sub_dir1
               - dir1_sub_dir1_file1
          - dir1_sub_dir2
          - dir1_sub_dir3
       - fileABC.ext
       - fileDEF.ext

---

是否有任何现有的JAVA实用程序可以帮助我了解目录（zip文件）中所有子目录的名称。例如，将“dir1”作为文件名“file.zip”的输入，并输出[dir1\u sub\u dir1，dir1\u sub\u dir2，dir1\u sub\u dir3]。解决这个问题的一种方法是使用ZipEntry。但是我们正在探索这个问题是否已经用JAVA中的某个库解决了。

以下是我快速组合的一些方法，您可能会发现这些方法对于从Zip文件中检索目录和/或文件名很有用。他们确实使用了拉链。按照你认为合适的方式来做：

/**
 * Returns a String Array of all directory paths contained within the 
 * supplied Zip file.<br><br>
 * 
 * The directory names returned are full paths.<br>
 * 
 * @param zipFilePath (String) The full Path and file name of the Zip 
 * file to retrieve directory paths from.<br>
 * 
 * @return (Single Dimensional String[] Array) A String Array containing 
 * all the directories contained within the supplied Zip file.
 */
public static String[] getZipFile_Directories(String zipFilePath) {
    java.util.zip.ZipFile zipFile = null;
    try {
        zipFile = new java.util.zip.ZipFile(zipFilePath);
    }
    catch (IOException ex) {
        Logger.getLogger("getZipFile_Directories() Method Error!").log(Level.SEVERE, null, ex);
        return null;
    }
    List<String> directories = new ArrayList<>();
    java.util.Enumeration<? extends java.util.zip.ZipEntry> entries = zipFile.entries();

    while (entries.hasMoreElements()) {
        java.util.zip.ZipEntry entry = entries.nextElement();
        if (entry.isDirectory()) {
            directories.add(entry.getName());
        }
    }
    return directories.toArray(new String[directories.size()]);
}

/**
 * Returns a String Array of all subdirectory paths that are contained 
 * within a possible directory path within the supplied Zip file.<br><br>
 * 
 * The subdirectory names returned are full paths.<br>
 * 
 * @param zipFilePath (String) The full Path and file name of the Zip 
 * file to retrieve subdirectory paths from.<br>
 * 
 * @param fromWithinDirectory (String) The directory path to retrieve 
 * subdirectories from. If there is a path in the zip file that is:<pre>
 * 
 *      {@code dir/folder1/folder2/}</pre><br>
 * 
 * and you want all the subdirectories contained within folder2 then you 
 * would supply:<pre>
 * 
 *     {@code dir/folder1/folder2/}</pre><br>
 * 
 * All subdirectories of {@code dir/folder1/folder2/} (if any) will be 
 * returned.
 * 
 * @return (Single Dimensional String[] Array) A String Array containing 
 * all the subdirectories contained within the supplied directory path 
 * which is also contained within the supplied Zip file.
 */
public static String[] getZipFile_SubDirectories(String zipFilePath, String fromWithinDirectory) {
    java.util.zip.ZipFile zipFile = null;
    try {
        zipFile = new java.util.zip.ZipFile(zipFilePath);
    }
    catch (IOException ex) {
        Logger.getLogger("getZipFile_SubDirectories() Method Error!").log(Level.SEVERE, null, ex);
        return null;
    }
    List<String> directories = new ArrayList<>();
    java.util.Enumeration<? extends java.util.zip.ZipEntry> entries = zipFile.entries();

    while (entries.hasMoreElements()) {
        java.util.zip.ZipEntry entry = entries.nextElement();
        if (entry.isDirectory()) {
            String dir = entry.getName();
            if (!dir.equalsIgnoreCase(fromWithinDirectory) && dir.contains(fromWithinDirectory)) {
                directories.add(dir);
            }
        }
    }
    return directories.toArray(new String[directories.size()]);
}

/**
 * Returns a String Array of all file paths contained within the 
 * supplied Zip file.<br><br>
 * 
 * The file names returned are full paths with file name.<br>
 * 
 * @param zipFilePath (String) The full Path and file name of the Zip 
 * file to retrieve file names from.<br>
 * 
 * @return (Single Dimensional String[] Array) A String Array containing 
 * all the <b>path and file names</b> contained within the supplied Zip 
 * file.
 */
public static String[] getZipFile_Files(String zipFilePath) {
    java.util.zip.ZipFile zipFile = null;
    try {
        zipFile = new java.util.zip.ZipFile(zipFilePath);
    }
    catch (IOException ex) {
        Logger.getLogger("getZipFile_Files() Method Error!").log(Level.SEVERE, null, ex);
        return null;
    }
    List<String> files = new ArrayList<>();
    java.util.Enumeration<? extends java.util.zip.ZipEntry> entries = zipFile.entries();

    while (entries.hasMoreElements()) {
        java.util.zip.ZipEntry entry = entries.nextElement();
        if (!entry.isDirectory()) {
            files.add(entry.getName());
        }
    }
    return files.toArray(new String[files.size()]);
}

/**
 * Returns a String Array of all file paths contained within the 
 * supplied directory contained within the supplied Zip file.<br><br>
 * 
 * The file names returned are full paths with file name.<br>
 * 
 * @param zipFilePath (String) The full Path and file name of the Zip 
 * file to retrieve file names from.<br>
 * 
 * @param fromWithinDirectory (String) The directory path to retrieve 
 * files from. If there is a path in the zip file that is:<pre>
 * 
 *      {@code dir/folder1/folder2/}</pre><br>
 * 
 * and you want all the files contained within folder1 then you 
 * would supply:<pre>
 * 
 *     {@code dir/folder1/}</pre><br>
 * 
 * All files contained within {@code dir/folder1/} (if any) will be 
 * returned.
 * 
 * @return (Single Dimensional String[] Array) A String Array containing 
 * all the <b>path and file names</b> contained within the supplied Zip 
 * file.
 */
public static String[] getZipFile_FilesFromDirectory(String zipFilePath, String fromWithinDirectory) {
    java.util.zip.ZipFile zipFile = null;
    try {
        zipFile = new java.util.zip.ZipFile(zipFilePath);
    }
    catch (IOException ex) {
        Logger.getLogger("getZipFile_FilesFromDirectory() Method Error!").log(Level.SEVERE, null, ex);
        return null;
    }
    List<String> files = new ArrayList<>();
    java.util.Enumeration<? extends java.util.zip.ZipEntry> entries = zipFile.entries();
    
    while (entries.hasMoreElements()) {
        java.util.zip.ZipEntry entry = entries.nextElement();
        String file = entry.getName();
                    
        if (!entry.isDirectory() && 
                file.substring(0, file.lastIndexOf("/") + 1)
                        .equalsIgnoreCase(fromWithinDirectory)) {
            files.add(file);
        }
    }
    return files.toArray(new String[files.size()]);
}

/**
*返回中包含的所有目录路径的字符串数组
*提供的Zip文件。


* 
*返回的目录名是完整路径。

* 
*@param zipFilePath（String）Zip文件的完整路径和文件名
*要从中检索目录路径的文件。

* 
*@return（一维字符串[]数组）包含
*提供的Zip文件中包含的所有目录。
*/
公共静态字符串[]getZipFile_目录（字符串zipFilePath）{
java.util.zip.ZipFile ZipFile=null；
试一试{
zipFile=newjava.util.zip.zipFile（zipFilePath）；
}
捕获（IOEX异常）{
Logger.getLogger（“getZipFile_Directories（）Method Error！”）.log（Level.SEVERE，null，ex）；
返回null；
}
列表目录=新的ArrayList（）；
java.util.Enumeration为什么你认为你需要一个ZipEntry的替代品？@Abra不是替代品，但不是使用ZipEntry逻辑再次实现它，如果一些库已经提供了这个功能，那么对于需要ZipEntry以外功能的人来说，Apache有一个通用的压缩库。但是，嗯，它没有解决这个问题你的需要是因为ZipEntry做了你想做的事情。
newZipFile（fileName）.stream（）.filter（ZipEntry:：isDirectory）.map（ZipEntry:：getName）.filter（n->n.startsWith（“dir1/”）
足够了吗？