Java 为什么这种流量不是';t在多个线程中执行?
我举了以下例子:Java 为什么这种流量不是';t在多个线程中执行?,java,reactor,Java,Reactor,我举了以下例子: Flux.just(1,2,3,4,5,6,7,8) .flatMap(integer -> { System.out.println("val:" + integer + ", thread:" + Thread.currentThread().getId()); return Mono.just(integer); }, 5)
Flux.just(1,2,3,4,5,6,7,8)
.flatMap(integer -> {
System.out.println("val:" + integer + ", thread:" + Thread.currentThread().getId());
return Mono.just(integer);
}, 5)
.repeat()
.subscribeOn(Schedulers.parallel())
.subscribe();
日志如下:
val:4, thread:14
val:5, thread:14
val:6, thread:14
val:7, thread:14
val:8, thread:14
val:1, thread:14
val:2, thread:14
val:3, thread:14
为什么到处都是同一根线??如何修改示例以使其在多个线程中执行?您需要使用
并行操作,如下所示:
Flux.just(1,2,3,4,5,6,7,8)
.parallel(2) // mention number of threads
.runOn(Schedulers.parallel())
.map(integer -> {
System.out.println("val:" + integer + ", thread:" + Thread.currentThread().getId());
return integer;
})
.subscribe();
如果希望每个重复的通量位于不同的线程上,可以在前面移动publishOn
,如下所示:
Flux.just(1,2,3,4,5,6,7,8)
.publishOn(Schedulers.parallel())//{
System.out.println(“val:+integer+”,线程:+thread.currentThread().getId());
返回Mono.just(整数);
}, 5)
.重复
.subscribe();
现在的输出是这样的:
val:1, thread:20
val:2, thread:20
val:3, thread:20
val:4, thread:20
val:5, thread:20
val:6, thread:20
val:7, thread:20
val:8, thread:20
val:1, thread:13
val:2, thread:13
val:3, thread:13
val:4, thread:13
val:5, thread:13
val:6, thread:13
val:7, thread:13
val:8, thread:13
如果希望每个整数位于不同的线程中,可以执行以下操作:
Flux.just(1,2,3,4,5,6,7,8)
.publishOn(Schedulers.parallel())//{
返回Mono.fromCallable(()->{
System.out.println(“val:+integer+”,线程:+thread.currentThread().getId());
返回整数;
}).publishOn(Schedulers.parallel())//
val:3, thread:16
val:2, thread:15
val:7, thread:20
val:8, thread:13
val:5, thread:18
val:6, thread:19
val:3, thread:17
val:5, thread:19
val:6, thread:20
val:1, thread:15
val:8, thread:14
val:4, thread:18
val:7, thread:13