Java 为什么我在使用SpringBoot应用程序的postman中没有收到错误消息

我想“管理员未找到”的消息显示在邮递员在无效登录，但我得到这个 作为邮递员输出

{
    "timestamp": "2020-05-19T13:59:01.172+00:00",
    "status": 404,
    "error": "Not Found",
    "message": "",
    "path": "/api/adminLogin"
}

AdminController.java

    @RestController
    @RequestMapping("/api")
    public class AdminController {

    @Autowired
    UserRepository userRepository; 

    @PostMapping("/adminLogin")
    public User login(@RequestBody User user) throws ResourceNotFoundException {

        User user1 = userRepository.findByUserName(user.getUserName());
        if(user1 != null && user1.getRole().equalsIgnoreCase("admin")) {
            return user1;
        }
        else 
        {
            throw new ResourceNotFoundException("Admin not found");
        }
    }

@ResponseStatus(HttpStatus.NOT_FOUND)
public class ResourceNotFoundException extends RuntimeException {

    private static final long serialVersionUID = 1L;

    public ResourceNotFoundException() {
        super();
    }

    public ResourceNotFoundException(String message) {
        super(message);
    }

    public ResourceNotFoundException(String message, Throwable cause) {
        super(message, cause);
    }
}

ResourceNotFoundException.java

    @RestController
    @RequestMapping("/api")
    public class AdminController {

    @Autowired
    UserRepository userRepository; 

    @PostMapping("/adminLogin")
    public User login(@RequestBody User user) throws ResourceNotFoundException {

        User user1 = userRepository.findByUserName(user.getUserName());
        if(user1 != null && user1.getRole().equalsIgnoreCase("admin")) {
            return user1;
        }
        else 
        {
            throw new ResourceNotFoundException("Admin not found");
        }
    }

@ResponseStatus(HttpStatus.NOT_FOUND)
public class ResourceNotFoundException extends RuntimeException {

    private static final long serialVersionUID = 1L;

    public ResourceNotFoundException() {
        super();
    }

    public ResourceNotFoundException(String message) {
        super(message);
    }

    public ResourceNotFoundException(String message, Throwable cause) {
        super(message, cause);
    }
}

我的邮递员网址

“我的管理员登录成功”运行正常

您可以使用它修改响应正文和状态代码。如果您想返回JSON格式，您应该创建一个新类，如下所示

@Data //lombok
public class ResponseModel {

    String message;

    public ResponseModel(String message) {
        this.message = message;
    }
}

 @PostMapping("/adminLogin")
    public ResponseEntity<?> login(@RequestBody User user) {

        User user1 = userRepository.findByUserName(user.getUserName());
        if(user1 != null && user1.getRole().equalsIgnoreCase("admin")) {
            return new ResponseEntity<>(user1, HttpStatus.OK);
        }
        else 
        {
            return new ResponseEntity<>(new ResponseModel("Admin not found"), HttpStatus.NOT_FOUND);
        }
    }

你的代码是这样的

@Data //lombok
public class ResponseModel {

    String message;

    public ResponseModel(String message) {
        this.message = message;
    }
}

 @PostMapping("/adminLogin")
    public ResponseEntity<?> login(@RequestBody User user) {

        User user1 = userRepository.findByUserName(user.getUserName());
        if(user1 != null && user1.getRole().equalsIgnoreCase("admin")) {
            return new ResponseEntity<>(user1, HttpStatus.OK);
        }
        else 
        {
            return new ResponseEntity<>(new ResponseModel("Admin not found"), HttpStatus.NOT_FOUND);
        }
    }

@PostMapping（/adminLogin）
公共响应身份登录（@RequestBody User）{
User user1=userRepository.findByUserName（User.getUserName（））；
if（user1！=null&&user1.getRole（）.equalsIgnoreCase（“admin”））{
返回新的响应属性（user1，HttpStatus.OK）；
}
其他的
{
返回新的ResponseEntity（新的ResponseModel（“未找到管理员”）、HttpStatus.not_found）；
}
}

将控制器响应概括为响应是标准模式

但是，您也可以使用以下方法解决您的特定问题：

在build.gradle/POM.XML中添加以下依赖项

runtimeOnly('org.springframework.boot:spring-boot-devtools')

pom.xml

    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-devtools</artifactId>
        <scope>runtime</scope>
    </dependency>

---

您将开始看到异常消息。

我通过在application.properties文件中包含以下代码解决了问题

server.error.include-message = always

---

您是在对邮递员进行GET还是POST查询测试？POST request@Ahmedrebaii如果您添加邮递员请求-url，method，您确定您的API路径：/API/adminLogin吗？@AhmedRebai是的。我的登录成功在application.properties文件中正常工作，谢谢