Java 双->；提取整数

如何提取/删除1.2中的1.0。所以我得到d2=0.2，d1=1，并且 当a=9->（9*3）/10时。d2=0.7，d1=2，当a=6-> (6*3)/10. d2=0.8，d1=1

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非常感谢。

只需从浮点值中减去整数部分：

int a = 4;
int b = 3;
int c = 10;
int d1 =(int) (double)(a*b)/c;
double d2 =(double)(a*b)/c;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);

Result: d1: 1 and d2: 1.2

int a = 4;
int b = 3;
int c = 10;
// Store the original value.
double original = (double)(a*b)/c;
int d1 = (int)(original);
// Get the difference between the original value and the floored one.
double d2 = original - d1;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);

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只需从浮点值中减去整数部分：

int a = 4;
int b = 3;
int c = 10;
// Store the original value.
double original = (double)(a*b)/c;
int d1 = (int)(original);
// Get the difference between the original value and the floored one.
double d2 = original - d1;
System.out.println("d1: " + d1);
System.out.println("d2: " + d2);

试试这个

double d = (double) (a*b)/c;
int intPart = (int) d;
double fracPart = d - intPart;

试试这个

double d = (double) (a*b)/c;
int intPart = (int) d;
double fracPart = d - intPart;

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怎么样

d2-=d1？多奇怪的问题。我找到了答案，谢谢。这比我想象的要容易。你说“我找到了解决办法”是什么意思？你问了，我们都给了你答案。下一步是选择最好的答案并接受它？多奇怪的问题。我找到了答案，谢谢。这比我想象的要容易。你说“我找到了解决办法”是什么意思？你问了，我们都给了你答案。下一步是选择最佳答案并接受它。