Java 如何在PageViewer中显示3个片段

在一个片段中，我试图创建一个包含3个片段的ViewPager，您可以在它们之间滑动。 4.我在理解结构和所犯的错误方面遇到了困难

public class ContactFragment extends Fragment {

FragmentPagerAdapter adapterViewPager;
private FragmentActivity myContext;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    ViewGroup rootView = (ViewGroup) inflater.inflate(R.layout.view_pager, container, false);

    ViewPager vpPager = (ViewPager) rootView.findViewById(R.id.vpPager);
    adapterViewPager = new MyPagerAdapter(myContext.getSupportFragmentManager());
    vpPager.setAdapter(adapterViewPager);

    return rootView;
}

@Override
public void onAttach(Activity activity) {
    myContext=(FragmentActivity) activity;
    super.onAttach(activity);
}

 public static class MyPagerAdapter extends FragmentPagerAdapter {
    private static int NUM_ITEMS = 3;

    public MyPagerAdapter(FragmentManager fragmentManager) {
        super(fragmentManager);
    }

    // Returns total number of pages
    @Override
    public int getCount() {
        return NUM_ITEMS;
    }

    // Returns the fragment to display for that page
    @Override
    public Fragment getItem(int position) {
        switch (position) {
            case 0: // Fragment # 0 - This will show FirstFragment
                return FirstFragment.newInstance(0, "Page # 1");
            case 1: // Fragment # 0 - This will show FirstFragment different title
                return FirstFragment.newInstance(1, "Page # 2");
            default:
                return null;
        }
    }

    // Returns the page title for the top indicator
    @Override
    public CharSequence getPageTitle(int position) {
        return "Page " + position;
    }

  }
}

我的ViewPager布局xml如下所示：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical">

    <android.support.v4.view.ViewPager
    android:id="@+id/vpPager"
    android:layout_width="match_parent"
    android:layout_height="wrap_content">

    <android.support.v4.view.PagerTabStrip
        android:id="@+id/pager_header"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_gravity="top"
        android:paddingBottom="4dp"
        android:paddingTop="4dp" />

    </android.support.v4.view.ViewPager>
</LinearLayout>

当我运行应用程序并加载片段时，它看起来是正确的，但当我尝试在pageviewer中滑动到新片段时，它崩溃了：

E/AndroidRuntime﹕ FATAL EXCEPTION: main
Process: org.example.magnusluca.drawertestapp, PID: 3624
java.lang.NullPointerException: Attempt to write to field 'android.support.v4.app.FragmentManagerImpl android.support.v4.app.Fragment.mFragmentManager' on a null object reference

用这个

@Override
public Fragment getItem(int position) {
    switch (position) {
        case 0: // Fragment # 0 - This will show FirstFragment
            return FirstFragment.newInstance(0, "Page # 1");
        case 1: // Fragment # 0 - This will show FirstFragment different title
            return FirstFragment.newInstance(1, "Page # 2");
        case 2:
            return FirstFragment.newInstance(2, "Page # 3");
        default:
            return new Fragment();
    }
}

---

您应该有3个开关盒，并且您的默认盒不应返回null

谢谢！但我不确定为什么会用无效的位置调用getItem？因为我们有一个getCount（）来保护位置值，对吗？

@Override
public Fragment getItem(int position) {
    switch (position) {
        case 0: // Fragment # 0 - This will show FirstFragment
            return FirstFragment.newInstance(0, "Page # 1");
        case 1: // Fragment # 0 - This will show FirstFragment different title
            return FirstFragment.newInstance(1, "Page # 2");
        case 2:
            return FirstFragment.newInstance(2, "Page # 3");
        default:
            return new Fragment();
    }
}