Java 读取不正确的JSON
我将JSON作为字符串Java 读取不正确的JSON,java,json,jackson,Java,Json,Jackson,我将JSON作为字符串 "{nameBitsCount=131}" 我需要,使用Jackson:1)正确解析这个JSON。2) 把结果放到地图上 但我有个例外 com.fasterxml.jackson.core.JsonParseException: Unexpected character ('n' (code 110)): was expecting double-quote to start field name at [Source: (String)"
"{nameBitsCount=131}"
我需要,使用Jackson:1)正确解析这个JSON。2) 把结果放到地图上
但我有个例外
com.fasterxml.jackson.core.JsonParseException: Unexpected character ('n' (code 110)): was expecting double-quote to start field name
at [Source: (String)"{nameBitsCount=131}";
PS:我想我需要把JSON的样式改成这样
"{\"nameBitsCount\":\"131\"}";
您发送的JSON无效
{nameBitsCount=131}
需要转换格式:
{"nameBitsCount":131}
在键周围添加{{{},并将{=}更改为{:}对JSON对象有效的JSON格式:
{
"Key" : "Value"
// "VALUE" if use for String and char put {"} around the value VALUE ex: 0.0 , 1 , -50 , FALSE
}
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这不是有效的JSON。您可能需要:“{”namebitscont“:131}”