Java 如何在Android中过滤JsonObject中的值?
如何从JsonObject解析所有文件上载日期Java 如何在Android中过滤JsonObject中的值?,java,android,json,android-json,Java,Android,Json,Android Json,如何从JsonObject解析所有文件上载日期 > {"-Kopv2EYUt7EeisRiiCz":{"deviceName":"LYF","fileUploadDate":"07\/12\/2017 2:00:57 PM"}, "-KopvA-cTtzgzSbsKTrw":{"deviceName":"LYF","fileUploadDate":"07\/12\/2017 2:01:29 PM",}} 使用GSON库 fileUploadDate = 07\/12\/2017 2:00
> {"-Kopv2EYUt7EeisRiiCz":{"deviceName":"LYF","fileUploadDate":"07\/12\/2017 2:00:57 PM"},
"-KopvA-cTtzgzSbsKTrw":{"deviceName":"LYF","fileUploadDate":"07\/12\/2017 2:01:29 PM",}}
使用GSON库
fileUploadDate = 07\/12\/2017 2:00:57 PM
fileUploadDate = "07\/12\/2017 2:01:29 PM
请尝试此操作以获得要解析的响应
我可以帮你吗
public void parseJson(String json){
Gson gson = new Gson();
Type stringStringMap = new TypeToken<Map<String, Map<String,String>>>(){}.getType();
Map<String,Map<String,String>> map = gson.fromJson(json, stringStringMap);
Iterator it = map.entrySet().iterator();
while (it.hasNext()) {
Map.Entry pair = (Map.Entry)it.next();
Map<String,String> innerMap = (Map<String,String>)pair.getValue();
getInnerMapDetail(innerMap);
it.remove(); // avoids a ConcurrentModificationException
}
}
public void getInnerMapDetail(Map<String,String> innerMap)
{
String fileUploadDate = innerMap.get("fileUploadDate"); // you will get here
}
}
此方法将返回密钥
try{
JSONObject jsonObject = new JSONObject(response);
List<String> keyList = getAllKeys(jsonObject);
for(String key : keyList){
JSONObject innerObject = jsonObject.getJSONObject(key);
String deviceName = innerObject.getString("deviceName");
String fileUploadDate = innerObject.getString("fileUploadDate");
System.out.println(deviceName +"--"+ fileUploadDate);
}
}catch(Exception e){
e.printStackTrace();
}
首先,您需要解析json对象并将其存储到字符串中,如下所示
private List<String> getAllKeys(JSONObject jsonObject) throws JSONException{
List<String> keys = new ArrayList<String>();
Iterator<?> iterator = jsonObject.keys();
while( iterator.hasNext() ) {
String key = (String)iterator.next();
keys.add(key);
}
return keys;
}
String fileUploadDate;
JSONObject -Kopv2EYUt7EeisRiiCz = new JSONObject;
fileUploadDate= sys.getString("fileUploadDate");
在你像那样改变字符串之后
String fileUploadDate;
JSONObject -Kopv2EYUt7EeisRiiCz = new JSONObject;
fileUploadDate= sys.getString("fileUploadDate");
您可以大胆地进行输出。参考此链接,我建议两种选择。第一种方法是检索已经过滤的json对象,这样您就可以使用过滤参数发出请求,服务器将过滤后的json发送给您,然后您可以在JsonObject中解析它。第二个选项是检索json,在JsonObject中解析它,然后实现自己的方法来按日期过滤。如果您在解析到JsonObject时遇到问题,StackOverflow中有许多已解决的问题。这是肯定的,替换方法将有所帮助。首先按原样获取jsonstring,然后替换即可。我同意上面的说法