Java 用于创建方法公共摘要的查询的字段

我在项目中使用controller、user、repository和service创建了一个登录用户。在控制器中，若电子邮件id和密码不为空，则登录，否则抛出异常“用户不存在”。我收到下面的错误，你能帮我解决这个问题吗

错误：

Error creating bean with name 'registrationRepository': FactoryBean threw exception on object creation; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract com.adventure.network.model.User com.adventure.network.repository.RegistrationRepository.findByEmailIdAndByPassword(java.lang.String,java.lang.String)! No property byPassword found for type User!

控制器：

@RestController
public class RegistrationController {

    @Autowired
    private RegistrationService service;

    @PostMapping("/login")
    public User loginUser(@RequestBody User user) throws Exception {
        String tempEmailId = user.getEmailId();
        String tempPassword = user.getPassword();
        
        User userObject = null;
        if(tempEmailId!=null && tempPassword!=null) {
            userObject = service.fetchUserByEmailIdByPassword(tempEmailId, tempPassword);   
        }
        if(userObject == null) {
            throw new Exception("User is not exict");
        }
        return userObject;
    }

服务：

@Service
public class RegistrationService {

    @Autowired 
    private RegistrationRepository repo;
    
    public User fetchUserByEmailIdByPassword(String email, String password) {
        return repo.findByEmailIdAndByPassword(email, password);
        
    }
}

存储库：

public interface RegistrationRepository extends JpaRepository<User, Integer> {

    public User findByEmailIdAndByPassword(String emailId, String password);
} 

public interface RegistrationRepository扩展了JpaRepository{
公共用户findByEmailIdAndByPassword（字符串emailId，字符串密码）；
} 

pom.xml

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.3.3.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>
    <groupId>com.adventure</groupId>
    <artifactId>network</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <name>network</name>
    <description>Demo project for Spring Boot</description>

    <properties>
        <java.version>11</java.version>
    </properties>

    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jpa</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>

        <dependency>
            <groupId>com.h2database</groupId>
            <artifactId>h2</artifactId>
            <scope>runtime</scope>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
            <exclusions>
                <exclusion>
                    <groupId>org.junit.vintage</groupId>
                    <artifactId>junit-vintage-engine</artifactId>
                </exclusion>
            </exclusions>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>

</project>

4.0.0
org.springframework.boot
spring启动程序父级
2.3.3.2发布
冒险
网络
0.0.1-快照
网络
SpringBoot的演示项目
11
org.springframework.boot
spring引导启动器数据jpa
org.springframework.boot
SpringBootStarterWeb
com.h2数据库
氢
运行时
org.springframework.boot
弹簧起动试验
测试
org.junit.vintage
朱尼特老式发动机
org.springframework.boot
springbootmaven插件

根据您的错误消息

找不到类型User的属性词

，它正在查找名为

byPassword

的属性，您需要在存储库中更改为

和密码，如下所示

public interface RegistrationRepository extends JpaRepository<User, Integer> {

    public User findByEmailIdAndPassword(String emailId, String password);
}

public interface RegistrationRepository扩展了JpaRepository{
公共用户findByEmailIdAndPassword（字符串emailId，字符串密码）；
}

Spring将解析by之后提到的每个属性，您只需要在方法的开头使用by

您还可以将名称更改为更易于阅读

public interface RegistrationRepository extends JpaRepository<User, Integer> {

    public User findUserByEmailIdAndPassword(String emailId, String password);
}

public interface RegistrationRepository扩展了JpaRepository{
公共用户FindUserByMaildAndPassword（字符串emailId，字符串密码）；
}
重命名方法
FindByeMaildAndPassword
为
FindByeMaildAndPassword
噢，将FindByeMaildAndPassword更改为FindByeMaildAndPassword后，它得到了修复。该方法可以是任何名称。为什么我的方法名称出现错误？不在存储库中。Spring解析存储库类的方法名，以了解用于搜索的
User
类的哪些属性。这就是JPA存储库在spring boot中的工作方式