Java 在Android中异步处理多个连续URL请求
我在请求多个连续url http请求时遇到问题。我的应用程序没有崩溃。在代码中使用loadUrls（）函数时，它连续执行6个url请求并将它们存储在一个数组中，但是我只能看到请求的第一个字符串响应Java 在Android中异步处理多个连续URL请求,java,android,android-asynctask,httprequest,kotlin,Java,Android,Android Asynctask,Httprequest,Kotlin,我在请求多个连续url http请求时遇到问题。我的应用程序没有崩溃。在代码中使用loadUrls（）函数时，它连续执行6个url请求并将它们存储在一个数组中，但是我只能看到请求的第一个字符串响应 fun loadUrls(){ val locationInput = “AsiaWorldExpo” val locationCoordinatesLong = 113.947 val locationCoordinatesLat = 22.2913 val myAPIKey = "REM
fun loadUrls(){
val locationInput = “AsiaWorldExpo”
val locationCoordinatesLong = 113.947
val locationCoordinatesLat = 22.2913
val myAPIKey = "REMOVED"
val transportMode = arrayListOf("&mode=driving" ,"&mode=walking", "&mode=bicycling",
"&mode=transit&transit_mode=bus", "mode=transit&transit_mode=subway", "mode=transit&transit_mode=train")
var requestURLArray = ArrayList<String>()
for (i in 0 until transportMode.size) {
requestURLArray.add("https://maps.googleapis.com/maps/api/distancematrix/json?units=metric&origins= " +
"$locationCoordinatesLat,$locationCoordinatesLong &destinations=$locationInput ${transportMode[i]} &key= $myAPIKey")
}
MyAsyncTask().execute(requestURLArray[0],requestURLArray[1],requestURLArray[2]
,requestURLArray[3], requestURLArray[4], requestURLArray[5])
}
override fun doInBackground(vararg p0: String?): String {
try {
val inString = ArrayList<String>()
for (i in 0 until p0.size) {
val url = URL(p0[i])
val urlConnect = url.openConnection() as HttpURLConnection
urlConnect.connectTimeout = 7000
inString.add(ConvertStreamToString(urlConnect.inputStream))
publishProgress(inString[i])
Log.d("APP_TEST", "" + p0[i]) //Added for debugging
try {
Thread.sleep(500)
} catch (e: InterruptedException) {}
}
}catch (r:Exception){}
return " "
}
override fun onProgressUpdate(vararg values: String?) {
try{
val jsonObject = ArrayList<String>()
for (i in 0 until values.size){
jsonObject.add(values[i]!!)
Log.d("Testing", "" + values[i]) //Added for debugging
}
idTextView2.text = jsonObject[1]
在每次迭代中，您都将创建名为inString的新实例，其类型为ArrayList。因此，当您创建新实例并向其中添加项时，该项始终为0。请通过将ArrayList实例创建移动到循环外部来修复它
override fun doInBackground(vararg p0: String?): String {
try {
val inString = ArrayList<String>()
for (i in 0 until p0.size) {
val url = URL(p0[i])
val urlConnect = url.openConnection() as HttpURLConnection
urlConnect.connectTimeout = 7000
inString.add(ConvertStreamToString(urlConnect.inputStream))
publishProgress(inString[i])
try {
Thread.sleep(500)
} catch (e: InterruptedException) {}
}
}catch (e:Exception){}
return " "
}
override-fun-doInBackground（vararg p0:String？）：String{
试一试{
val inString=ArrayList（）
对于（i在0中，直到p0.size）{
val url=url（p0[i]）
val urlConnect=url.openConnection（）作为HttpURLConnection
urlConnect.connectTimeout=7000
inString.add（ConvertStreamToString（urlConnect.inputStream））
出版进度（仪表[i]）
试一试{
线程。睡眠（500）
}catch（e:InterruptedException）{}
}
}捕获（e:异常）{}
返回“”
}
< /代码>我已经从您的代码中删除了API密钥。考虑到它是否泄露了，所以我建议禁用它并获得一个新的密钥。您几乎不应该在堆栈溢出或其他公共平台上发布API密钥。非常感谢，您是否可以提供LogCCAT？也可以添加<代码> E.PrimtStAccTrace（）。catchoverride fun doInBackground(vararg p0: String?): String {
try {
val inString = ArrayList<String>()
for (i in 0 until p0.size) {
val url = URL(p0[i])
val urlConnect = url.openConnection() as HttpURLConnection
urlConnect.connectTimeout = 7000
inString.add(ConvertStreamToString(urlConnect.inputStream))
publishProgress(inString[i])
try {
Thread.sleep(500)
} catch (e: InterruptedException) {}
}
}catch (e:Exception){}
return " "
}