Java-使用HtmlUnit发送post请求

在这方面找不到任何帮助，但我一直在尝试使用HtmlUnit发送post请求。我的密码是：

final WebClient webClient = new WebClient();

// Instead of requesting the page directly we create a WebRequestSettings object
WebRequest requestSettings = new WebRequest(
  new URL("www.URLHERE.com"), HttpMethod.POST);

// Then we set the request parameters
requestSettings.setRequestParameters(new ArrayList());
requestSettings.getRequestParameters().add(new NameValuePair("name", "value"));
// Finally, we can get the page
HtmlPage page = webClient.getPage(requestSettings);

---

有没有更简单的方法来执行POST请求？

有n个可能的库，您可以使用这些库调用rest web服务

1） Apache Http客户端 2） 广场改造 3） 谷歌截击

我使用了Http Apache客户端，并对两者进行了改进。两者都很棒

下面是Apache HTTP客户端发送Post请求的代码示例

String token = null;

    HttpClient httpClient = HttpClientBuilder.create().build();
    HttpPost postRequest = new HttpPost(LOGIN_URL);
    StringBuilder sb = new StringBuilder();
    sb.append("{\"userName\":\"").append(user).append("\",").append("\"password\":\"").append(password).append("\"}");
    String content = sb.toString();
    StringEntity input = new StringEntity(content);
    input.setContentType("application/json");
    postRequest.setHeader("Content-Type", "application/json");
    postRequest.setHeader("Accept", "application/json");

    postRequest.setEntity(input);

    HttpResponse response = httpClient.execute(postRequest);

    if (response.getStatusLine().getStatusCode() != 201)
    {
        throw new RuntimeException("Failed : HTTP error code : " + response.getStatusLine().getStatusCode());
    }

    Header[] headers = response.getHeaders("X-Auth-Token");

    if (headers != null && headers.length > 0)
    {
        token = headers[0].getValue();
    }

    return token;

就是这样做的

public void post() throws Exception
{

    URL url = new URL("YOURURL");
    WebRequest requestSettings = new WebRequest(url, HttpMethod.POST);

    requestSettings.setAdditionalHeader("Accept", "*/*");
    requestSettings.setAdditionalHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
    requestSettings.setAdditionalHeader("Referer", "REFURLHERE");
    requestSettings.setAdditionalHeader("Accept-Language", "en-US,en;q=0.8");
    requestSettings.setAdditionalHeader("Accept-Encoding", "gzip,deflate,sdch");
    requestSettings.setAdditionalHeader("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
    requestSettings.setAdditionalHeader("X-Requested-With", "XMLHttpRequest");
    requestSettings.setAdditionalHeader("Cache-Control", "no-cache");
    requestSettings.setAdditionalHeader("Pragma", "no-cache");
    requestSettings.setAdditionalHeader("Origin", "https://YOURHOST");

    requestSettings.setRequestBody("REQUESTBODY");

    Page redirectPage = webClient.getPage(requestSettings);
}

---

您可以根据需要自定义它。添加/删除标题、添加/删除请求正文等…

不使用Web Client.Hello。你想要一个更简单的方法。好的，但是你能解释一下你在片段中发现了什么困难或复杂的地方吗？对不起，我不明白。谢谢你的回复。我使用了Apache httpclient，但我必须访问的站点需要您等待5秒进行ddos保护，因此当我使用httpclient时，我只需从ddos保护中获取源代码。重要的是，我可以获得实际页面的源代码，因为我需要在帖子发布后解析响应。未定义，我不知道用哪种方式，使用ApacheHTTP客户端和您建议的其他api比使用htmlunit更容易。你能和我辩论一下吗？