java xpath将格式化日期与xml中的当前日期进行比较
我有这样的XML文件:java xpath将格式化日期与xml中的当前日期进行比较,java,xml,date,xpath,Java,Xml,Date,Xpath,我有这样的XML文件: <books> <book> <id>1</id> <validFrom>23.11.2012</validFrom> <validTo>26.09.2012</validTo> </book> <book> <id>2</id> <validFrom>14.09.2012<
<books>
<book>
<id>1</id>
<validFrom>23.11.2012</validFrom>
<validTo>26.09.2012</validTo>
</book>
<book>
<id>2</id>
<validFrom>14.09.2012</validFrom>
<validTo>01.08.2012</validTo>
</book>
1.
23.11.2012
26.09.2012
2.
14.09.2012
01.08.2012
我想从这个xml文件中删除所有书籍,其中日期validTo早于当前日期,但我在XPath中的查询方面有问题
我试过不同的方法
XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xpath = xPathFactory.newXPath();
XPathExpression expr
= xpath.compile("//book[validTo < fn:current-date()]");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++) {
removeFindNodes()
}
XPathFactory XPathFactory=XPathFactory.newInstance();
XPath=xPathFactory.newXPath();
XPathExpression
=xpath.compile(//book[validTo
如何设置有效日期的格式,以便与当前日期进行比较
感谢您的帮助
xsd:date
希望格式为yyyy-MM-dd
,而您的格式为dd.MM.yyyy
。您可以尝试结合使用子字符串
、翻译
、和concat
来转换格式,但到那时,XPath表达式将变得稍微复杂。另一种更容易阅读的解决方案是将所有有效节点提取到
节点,然后与Java进行比较:
XPathExpression expr = xpath.compile("//book/validTo");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
DateFormat df = new SimpleDateFormat("dd.MM.yyyy");
Calendar now = Calendar.getInstance();
now.set(Calendar.HOUR_OF_DAY, 0);
now.set(Calendar.MINUTE, 0);
now.set(Calendar.SECOND, 0);
now.set(Calendar.MILLISECOND, 0);
for (int i = 0; i < nodes.getLength(); i++) {
Node validToNode = nodes.item(i);
Date validTo = df.parse(validToNode.getTextContent());
if (validTo.compareTo(now.getTime()) < 0) {
Node bookNode = validToNode.getParentNode();
removeNode(bookNode);
}
}
XPathExpression expr=xpath.compile(“//book/validTo”);
Object result=expr.evaluate(doc,XPathConstants.NODESET);
节点列表节点=(节点列表)结果;
DateFormat df=新的SimpleDateFormat(“dd.MM.yyyy”);
Calendar now=Calendar.getInstance();
now.set(Calendar.HOUR\u OF_DAY,0);
现在。设置(Calendar.MINUTE,0);
现在。设置(日历秒,0);
now.set(Calendar.millis秒,0);
对于(int i=0;i