Java org.xml.sax.SAXException:SimpleDeserializer遇到子元素,这不是预期的
我有以下文件,我Java org.xml.sax.SAXException:SimpleDeserializer遇到子元素,这不是预期的,java,xml,web-services,soap,sax,Java,Xml,Web Services,Soap,Sax,我有以下文件,我cURL: <?xml version="1.0" encoding="UTF-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org
cURL
:
<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soap:Body>
<ProcessMessage xmlns="http://www.user.com/test/">
<envelope>Encoded XML request message will go here</envelope>
</ProcessMessage>
</soap:Body>
</soap:Envelope>
当我使用带有CDATA
元素的文件时,一切都正常工作
<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soap:Body>
<ProcessMessage xmlns="http://www.user.com/test/">
<![CDATA[<?xml version="1.0" encoding="UTF-8"?>
<envelope>Encoded XML request message will go here</envelope>
]]>
</ProcessMessage>
</soap:Body>
</soap:Envelope>
编码的XML请求消息将显示在此处
]]>
你知道我如何在没有CDATA部分的情况下接受XML文件吗?引用:“格式良好的XML中只允许有一个XML声明,如果在任何地方,它必须位于顶部。”
见:
因此,如果你能摆脱第二个
你就可以了。问题不在于
<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soap:Body>
<ProcessMessage xmlns="http://www.user.com/test/">
<![CDATA[<?xml version="1.0" encoding="UTF-8"?>
<envelope>Encoded XML request message will go here</envelope>
]]>
</ProcessMessage>
</soap:Body>
</soap:Envelope>