在多播Java中不使用VirtualBox作为网络接口？

我在java中使用多播时遇到了一个问题。我正在尝试使用一个简单的发送方-接收方程序来测试多播，该程序应该在同一子网中的两台计算机上的Windows上运行（请参阅后面的代码）。问题是它使用了我的一个VirtualBox接口作为

网络接口

，而不是我的无线网卡，因此无法通过两台计算机发送数据（我尝试过）。如果我手动设置要使用的接口（请参阅代码中的注释），它可以在同一子网中的两台计算机上完美工作（这是我的目标）。 我的问题是：是否有任何解决方法可以在默认情况下不选择VirtualBox接口，或者迭代所有接口（知道VB接口与我的无线网卡具有完全相同的属性…甚至

isVirtual

return

false

）

这是发件人：

public class MulticastSender extends Thread {

    final static String INET_ADDR = "239.192.0.1";

    MulticastSocket serverSocket;

    public void run() {
        // Get the address that we are going to connect to.
        InetAddress addr = null;
        try {
            addr = InetAddress.getByName(INET_ADDR);
        } catch (UnknownHostException e) {
            e.printStackTrace();
        }

        // Open a new MulticastSocket, which will be used to send the data.
        try {
            serverSocket = new MulticastSocket();

            // if I set it manually it works (here goes the IP of my PC n°1)
            //serverSocket.setInterface(InetAddress.getByName("IP of my first PC"));

            serverSocket.joinGroup(addr);

            for (int i = 0; i < 100; i++) {
                String msg = "Sent message no " + i;

                // Create a packet that will contain the data
                // (in the form of bytes) and send it.
                DatagramPacket msgPacket = new DatagramPacket(msg.getBytes(),
                        msg.getBytes().length, addr, 8080);
                serverSocket.send(msgPacket);

                System.out.println("Server sent packet with msg: " + msg);
                try {
                    Thread.sleep(1000);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            serverSocket.close();
        } catch (IOException ex) {
            ex.printStackTrace();
        }
    }
}

public class MulticastReceiver implements Runnable {

    final static String INET_ADDR = "239.192.0.1";

    public void run() {
        // Get the address that we are going to connect to.
        InetAddress address = null;
        try {
            address = InetAddress.getByName(INET_ADDR);
            MulticastSocket clientSocket = new MulticastSocket(8080);

            // if I set it manually it works (here goes the IP of my PC n°2)
            //clientSocket.setInterface(InetAddress.getByName("IP of my second PC"));

            // Create a buffer of bytes, which will be used to store
            // the incoming bytes containing the information from the server.
            // Since the message is small here, 256 bytes should be enough.
            byte[] buf = new byte[256];

            //Join the Multicast group.
            clientSocket.joinGroup(address);

            while (true) {
                // Receive the information and print it.
                DatagramPacket msgPacket = new DatagramPacket(buf, buf.length);
                clientSocket.receive(msgPacket);
                String msg = new String(buf, 0, buf.length);
                System.out.println("Received msg: " + msg);
            }
        } catch (IOException ex) {
            ex.printStackTrace();
        }
    }
}