我无法将输入从对象数组传递到java方法
我正在制作一个java程序来计算三角形和正方形的面积和周长,我需要创建一个三角形和正方形类的对象,并从中获取输入。我已经为它编写了一些代码,但它没有将输入作为参数。我不明白可能是什么问题。请帮忙 geometricFigure.java-这是一个接口我无法将输入从对象数组传递到java方法,java,arrays,object,input,methods,Java,Arrays,Object,Input,Methods,我正在制作一个java程序来计算三角形和正方形的面积和周长,我需要创建一个三角形和正方形类的对象,并从中获取输入。我已经为它编写了一些代码,但它没有将输入作为参数。我不明白可能是什么问题。请帮忙 geometricFigure.java-这是一个接口 public interface GeometricFigure { public void area(double sideOne, double sideTwo, double sideThree); public void p
public interface GeometricFigure {
public void area(double sideOne, double sideTwo, double sideThree);
public void perimeter(double sideOne, double sideTwo, double sideThree);
public void print();
}
java-这是具有main函数的文件
public class trisqu{
public static void main(String[] args) {
double sideOne, sideTwo , sideThree;
//Triangle tr = new GeometricFigure();
Triangle[] tr = new Triangle[3];
tr[0] = new Triangle(4,9,12);
tr[1] = new Triangle(9,16,25);
tr[2] = new Triangle(8,12,14);
for (int i=0;i<tr.length;i++){
System.out.println("Triangle Object :"+(i+1)+" ");
tr[i].area(sideOne, sideTwo, sideThree);
tr[i].perimeter(sideOne, sideTwo, sideThree);
tr[i].print();
}
//Square sq = new GeometricFigure();
Square[] sq = new Square[3];
sq[0] = new Square(8);
sq[1] = new Square(32);
sq[2] = new Square(16);
for (int i=0;i<sq.length;i++){
System.out.println("Square Object : "+(i+1)+ " ");
sq[i].area(sideOne, sideTwo, sideThree);
sq[i].perimeter(sideOne, sideTwo, sideThree);
sq[i].print();
}
}
}
java-这是试验的文件`
import java.lang.Math;
public class Triangle implements GeometricFigure{
private double sideOne, sideTwo, sideThree,TriArea,TriPerimeter;
public Triangle(double sideOne, double sideTwo, double sideThree){
}
double halfp = (sideOne + sideTwo + sideThree)/2;
@Override
public void area(double sideOne, double sideTwo, double sideThree){
TriArea = Math.sqrt(halfp*(halfp - sideOne)*(halfp - sideTwo)*(halfp - sideThree));
}
@Override
public void perimeter(double sideOne, double sideTwo, double sideThree){
TriPerimeter = sideOne + sideTwo + sideThree;
}
@Override
public void print(){
System.out.print("Area = "+TriArea+" Perimeter = "+TriPerimeter);
System.out.println("\n");
}
}
请帮助我,我是java初学者或任何语言。 < P>有很多事情要考虑。< /P> 首先,我相信您使用接口的方式是错误的,在我看来,接口应该描述行为(因此这里的抽象类更可取,因为实现接口的类已经具有对象的值,所以不需要传递它们) 其次,您将参数传递给构造函数,但没有将它们分配给类属性,这是一个问题 第三,当您在main中传递
sideOne、sideTwo、sideTwo
参数时,它们还没有初始化,但是最重要的是您根本不需要传递它们
总之,我向你推荐这样的东西:
public interface GeometricFigure {
public double getArea();
public double getPerimeter();
public void print();
}
接下来,实现它的类应该如下所示:
public class Square implements GeometricFigure {
private double side; // note that I have removed the area and perimeter variables
Square(double side) {
this.side = side;
}
@Override
public double getArea() {
return side * side;
}
@Override
public double getPerimeter() {
return side * 4;
}
@Override
public void print() {
System.out.print("Area = " + getArea() + " Perimeter = " + getPerimeter());
System.out.println("\n");
}
}
for (int i=0;i<sq.length;i++){
System.out.println("Square Object : "+(i+1)+ " \n" + sq[i]);
}
请注意,类的结构已更改。这样做的目的是,当侧面发生变化时(如果可能的话),我们不需要更新区域
和周长
属性
我相信你可以自己做三角形的事情
现在主要部分是:
public static void main(String[] args) {
Triangle[] tr = new Triangle[3];
tr[0] = new Triangle(4,9,12);
tr[1] = new Triangle(9,16,25);
tr[2] = new Triangle(8,12,14);
for (int i=0;i<tr.length;i++){
System.out.println("Triangle Object :"+(i+1)+" ");
tr[i].print();
}
Square[] sq = new Square[3];
sq[0] = new Square(8);
sq[1] = new Square(32);
sq[2] = new Square(16);
for (int i=0;i<sq.length;i++){
System.out.println("Square Object : "+(i+1)+ " ");
sq[i].print();
}
}
然后大体上只需做以下几点:
public class Square implements GeometricFigure {
private double side; // note that I have removed the area and perimeter variables
Square(double side) {
this.side = side;
}
@Override
public double getArea() {
return side * side;
}
@Override
public double getPerimeter() {
return side * 4;
}
@Override
public void print() {
System.out.print("Area = " + getArea() + " Perimeter = " + getPerimeter());
System.out.println("\n");
}
}
for (int i=0;i<sq.length;i++){
System.out.println("Square Object : "+(i+1)+ " \n" + sq[i]);
}
for(int i=0;i@MayankSharma不客气,先生,如果您对答案满意,请将其标记为选定答案