java.lang.NullPointerException:尝试调用虚拟方法“java.lang.String android.os.Bundle.getString(java.lang.String)”
我是Android应用程序开发的初学者。我试图使用intent将评级从第二个活动发送到主活动。执行此操作时,我收到错误:java.lang.NullPointerException:尝试在null上调用虚拟方法“java.lang.String android.os.Bundle.getStringjava.lang.String”更改以下内容:java.lang.NullPointerException:尝试调用虚拟方法“java.lang.String android.os.Bundle.getString(java.lang.String)”,java,android,nullpointerexception,Java,Android,Nullpointerexception,我是Android应用程序开发的初学者。我试图使用intent将评级从第二个活动发送到主活动。执行此操作时,我收到错误:java.lang.NullPointerException:尝试在null上调用虚拟方法“java.lang.String android.os.Bundle.getStringjava.lang.String”更改以下内容: enter code here public class MainActivity extends AppCompatActivity { TextV
enter code here
public class MainActivity extends AppCompatActivity {
TextView tv;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setTextInTextView();
setContentView(R.layout.activity_main);
}
public void setTextInTextView(){
tv = (TextView) findViewById(R.id.rate);
Bundle extra = getIntent().getExtras();
tv.setText(""+extra.getString("key"));
}
public void go(View view) {
Intent i = new Intent(MainActivity.this,Activity2.class);
startActivity(i);
}
enter code here
public class Activity2 extends AppCompatActivity {
RatingBar rb;
float str;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_2);
rb = (RatingBar)findViewById(R.id.rt);
}
public void submit(View view) {
String st = String.valueOf(rb.getRating());
Intent i = new Intent(Activity2.this,MainActivity.class);
i.putExtra("key",""+st);
startActivity(i);
}
}
为此:
public void setTextInTextView(){
tv = (TextView) findViewById(R.id.rate);
Bundle extra = getIntent().getExtras();
tv.setText(""+extra.getString("key"));
}
感谢Omid的回复,但仍然显示出相同的错误;在setContentViewR.layout.activity_main之后;在那之前,我不知道。。。我得到了它。
public void setTextInTextView(){
tv = (TextView) findViewById(R.id.rate);
Bundle extra = getIntent().getExtras();
if(extra != null)
tv.setText(""+extra.getString("key"));
}