Java 映射中集合的通配符-返回类型不兼容-为什么?
以下是设置我的问题情况的示例代码: Foo接口:Java 映射中集合的通配符-返回类型不兼容-为什么?,java,generics,dictionary,wildcard,return-type,Java,Generics,Dictionary,Wildcard,Return Type,以下是设置我的问题情况的示例代码: Foo接口: interface Foo<K> { Map<K, Set<? extends Foo<K>>> map(); Set<? extends Foo<K>> set(); } interface Bar<K> extends Foo<K> {} 接口Foo{ Map原始示例很复杂,我将使用一些简化 在您的示例中,Foo.set()返
interface Foo<K> {
Map<K, Set<? extends Foo<K>>> map();
Set<? extends Foo<K>> set(); }
interface Bar<K> extends Foo<K> {}
接口Foo{
Map原始示例很复杂,我将使用一些简化
在您的示例中,Foo.set()
返回SetSee:,
class FooBar<K> implements Bar<K> {
Map<K, Set<Bar<K>>> map;
Set<Bar<K>> set;
@Override
public Map<K, Set<? extends Foo<K>>> map() {
return map; }
// For the above, Eclipse is yelling:
// Type mismatch: cannot convert from
// Map<K,Set<Bar<K>>> to Map<K,Set<? extends Foo<K>>>
// But Eclipse likes the following:
@Override
public Set<? extends Foo<K>> set() {
return set; }
}
class FooBar<K> implements Bar<K> {
Map<K, Set<Bar<K>>> map;
Set<Bar<K>> set;
@Override
public Map<K, Set<Bar<K>>> map() {
return map; }
// For the above, Eclipse is yelling:
// The return type is incompatible with Foo<K>.map()
// But Eclipse, again, likes the following:
@Override
public Set<Bar<K>> set() {
return set; }
}
Number number5 = 5;
Integer int5 = 5;
number5 = int5; //OK
List<Number> listNumber5 = Arrays.asList(number5);
List<Integer> listInt5 = Arrays.asList(int5);
listNumber5 = listInt5; //ERROR
List<? extends Number> listExtendsNumber5 = Arrays.asList(number5);
listExtendsNumber5 = listInt5; // OK