在java中有没有存储条件语句的方法?
我想知道是否有任何方法可以在java中存储if-else条件?我的意思是有一个变量来表示条件。这是我的原始代码在java中有没有存储条件语句的方法?,java,android,if-statement,conditional-statements,Java,Android,If Statement,Conditional Statements,我想知道是否有任何方法可以在java中存储if-else条件?我的意思是有一个变量来表示条件。这是我的原始代码 private OnClickListener click2 = new OnClickListener() { @Override public void onClick(View v) { tv1.setText(""); List<Integer> mClickedBu
private OnClickListener click2 = new OnClickListener() {
@Override
public void onClick(View v) {
tv1.setText("");
List<Integer> mClickedButtonIds = new ArrayList<Integer>();
int[] mDesiredOrder = new int[] { ans1.getId(), ans2.getId(), ans3.getId(),
ans4.getId(), ans5.getId() };
mClickedButtonIds.add(v.getId());
if (mClickedButtonIds.size() >= mDesiredOrder.length )
{
if (mClickedButtonIds.get(0) == mDesiredOrder[0]
&& mClickedButtonIds.get(1) == mDesiredOrder[1]
&& mClickedButtonIds.get(2) == mDesiredOrder[2]
&& mClickedButtonIds.get(3) == mDesiredOrder[3]
&& mClickedButtonIds.get(4) == mDesiredOrder[4]
)
{
tv1.setText("Correct!");
}
else
{
tv1.setText("Try Again!");
}
mClickedButtonIds.clear();
}
}
};
private OnClickListener click2=new OnClickListener(){
@凌驾
公共void onClick(视图v){
tv1.setText(“”);
List mClickedButtonIds=newarraylist();
int[]mDesiredOrder=new int[]{ans1.getId(),ans2.getId(),ans3.getId(),
ans4.getId(),ans5.getId()};
添加(v.getId());
if(mclickedbutonids.size()>=mDesiredOrder.length)
{
if(mclickedbutonids.get(0)=mDesiredOrder[0]
&&mClickedButtonIds.get(1)=mDesiredOrder[1]
&&mClickedButtonIds.get(2)=mDesiredOrder[2]
&&mClickedButtonIds.get(3)=mDesiredOrder[3]
&&mClickedButtonIds.get(4)=mDesiredOrder[4]
)
{
tv1.setText(“正确!”);
}
其他的
{
tv1.setText(“再试一次!”);
}
mClickedButtonIds.clear();
}
}
};
我打算把它改成这样
private OnClickListener click2 = new OnClickListener() {
@Override
public void onClick(View v) {
tv1.setText("");
List<Integer> mClickedButtonIds = new ArrayList<Integer>();
int[] mDesiredOrder = new int[] { ans1.getId(), ans2.getId(), ans3.getId(),
ans4.getId(), ans5.getId(), ans6.getId() };
switch (main)
{
case 4 : Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0]
&& mClickedButtonIds.get(1) == mDesiredOrder[1]
&& mClickedButtonIds.get(2) == mDesiredOrder[2]
&& mClickedButtonIds.get(3) == mDesiredOrder[3];
case 5 : Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0]
&& mClickedButtonIds.get(1) == mDesiredOrder[1]
&& mClickedButtonIds.get(2) == mDesiredOrder[2]
&& mClickedButtonIds.get(3) == mDesiredOrder[3]
&& mClickedButtonIds.get(4) == mDesiredOrder[4];
case 6: Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0]
&& mClickedButtonIds.get(1) == mDesiredOrder[1]
&& mClickedButtonIds.get(2) == mDesiredOrder[2]
&& mClickedButtonIds.get(3) == mDesiredOrder[3]
&& mClickedButtonIds.get(4) == mDesiredOrder[4]
&& mClickedButtonIds.get(5) == mDesiredOrder[5];
}
mClickedButtonIds.add(v.getId());
if (mClickedButtonIds.size() >= mDesiredOrder.length )
{
if (x)
{
tv1.setText("Correct!");
}
else
{
tv1.setText("Try Again!");
}
mClickedButtonIds.clear();
}
}
};
private OnClickListener click2=new OnClickListener(){
@凌驾
公共void onClick(视图v){
tv1.setText(“”);
List mClickedButtonIds=newarraylist();
int[]mDesiredOrder=new int[]{ans1.getId(),ans2.getId(),ans3.getId(),
ans4.getId(),ans5.getId(),ans6.getId()};
开关(主)
{
案例4:变量x=mClickedButtonIds.get(0)=mDesiredOrder[0]
&&mClickedButtonIds.get(1)=mDesiredOrder[1]
&&mClickedButtonIds.get(2)=mDesiredOrder[2]
&&mClickedButtonIds.get(3)=mDesiredOrder[3];
案例5:变量x=mClickedButtonIds.get(0)=mDesiredOrder[0]
&&mClickedButtonIds.get(1)=mDesiredOrder[1]
&&mClickedButtonIds.get(2)=mDesiredOrder[2]
&&mClickedButtonIds.get(3)=mDesiredOrder[3]
&&mClickedButtonIds.get(4)=mDesiredOrder[4];
案例6:变量x=mClickedButtonIds.get(0)=mDesiredOrder[0]
&&mClickedButtonIds.get(1)=mDesiredOrder[1]
&&mClickedButtonIds.get(2)=mDesiredOrder[2]
&&mClickedButtonIds.get(3)=mDesiredOrder[3]
&&mClickedButtonIds.get(4)=mDesiredOrder[4]
&&mClickedButtonIds.get(5)=mDesiredOrder[5];
}
添加(v.getId());
if(mclickedbutonids.size()>=mDesiredOrder.length)
{
if(x)
{
tv1.setText(“正确!”);
}
其他的
{
tv1.setText(“再试一次!”);
}
mClickedButtonIds.clear();
}
}
};
变量x
是我想问的问题。是否有任何方法可以这样做,或者是否有任何变量可以存储if-else条件。原因原代码,它被固定为5次点击。现在,我希望根据用户需要点击多少来改变所需的点击次数。< P>根据代码片段,考虑循环:
boolean result = true;
for (int i = 0; i < main; ++i) {
result = result && mClickedButtonIds.get(i) == mDesiredOrder[i];
if (!result)
break; // short-circuit out from loop if false
}
// now you can use "result" to test whether the condition matched all "main" ids
if (result) {
// correct
} else {
// bzzt, try again
}
布尔结果=true;
对于(int i=0;i<代码> > p>基于代码段,考虑循环:
boolean result = true;
for (int i = 0; i < main; ++i) {
result = result && mClickedButtonIds.get(i) == mDesiredOrder[i];
if (!result)
break; // short-circuit out from loop if false
}
// now you can use "result" to test whether the condition matched all "main" ids
if (result) {
// correct
} else {
// bzzt, try again
}
布尔结果=true;
对于(int i=0;i<代码> > p>基于代码段,考虑循环:
boolean result = true;
for (int i = 0; i < main; ++i) {
result = result && mClickedButtonIds.get(i) == mDesiredOrder[i];
if (!result)
break; // short-circuit out from loop if false
}
// now you can use "result" to test whether the condition matched all "main" ids
if (result) {
// correct
} else {
// bzzt, try again
}
布尔结果=true;
对于(int i=0;i<代码> > p>基于代码段,考虑循环:
boolean result = true;
for (int i = 0; i < main; ++i) {
result = result && mClickedButtonIds.get(i) == mDesiredOrder[i];
if (!result)
break; // short-circuit out from loop if false
}
// now you can use "result" to test whether the condition matched all "main" ids
if (result) {
// correct
} else {
// bzzt, try again
}
布尔结果=true;
对于(int i=0;i
如果我理解正确,您希望x是一个可以通过编程更改的条件(但它符合某些结构),那么您可以使用接口问题
和实现该接口的类来实现这一点
public interface Question {
boolean getResponse(String condition1, int condition2);
}
public class StringIsLongCondition implements Question{
public boolean getResponse(String condition1, int condition2) {
return condition1.length()>condition2;
}
}
public class StringIsShortCondition implements Question{
public boolean getResponse(String condition1, int condition2) {
return condition1.length()<condition2;
}
}
如果我理解正确,您希望x是一个可以通过编程更改的条件(但它符合某些结构),那么您可以使用接口问题
和实现该接口的类来实现这一点
public interface Question {
boolean getResponse(String condition1, int condition2);
}
public class StringIsLongCondition implements Question{
public boolean getResponse(String condition1, int condition2) {
return condition1.length()>condition2;
}
}
public class StringIsShortCondition implements Question{
public boolean getResponse(String condition1, int condition2) {
return condition1.length()<condition2;
}
}
如果我理解正确,您希望x是一个可以通过编程更改的条件(但它符合某些结构),那么您可以使用接口问题来实现这一点