Java 使用JAXB从MAP创建XML
我想从Java.util.Map创建XML 我将值放在该映射中,并尝试创建可配置的根元素和从该映射创建的子元素的XMLJava 使用JAXB从MAP创建XML,java,xml,jaxb,Java,Xml,Jaxb,我想从Java.util.Map创建XML 我将值放在该映射中,并尝试创建可配置的根元素和从该映射创建的子元素的XML Map mp = new HashMap(); mp.put("key","shaon"): mp.put("newKey","newValue"); XML将类似于: <shaonsXML> <key>shaon</key> <newKey> newValue </newKey> </
Map mp = new HashMap();
mp.put("key","shaon"):
mp.put("newKey","newValue");
XML将类似于:
<shaonsXML>
<key>shaon</key>
<newKey> newValue </newKey>
</shaonsXML>
邵
新价值
我已经看到了使用JAXB的示例,但这些示例并没有像我试图生成的那个样创建XML标记
谁能给我一些链接或建议?提前谢谢
我采纳了这些建议:以及
但它会生成这种XML:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
<mapProperty>
<item>
<key>KEY1</key>
<value>SHAON</value>
</item>
<item>
<key>newKEY</key>
<value>newValue</value>
</item>
</mapProperty>
</root>
关键1
邵
纽基
新价值
我做到了!用过的例子
从上面的帖子:创建这个类:
public class MapAdapter extends XmlAdapter<MapWrapper, Map<String, String>>{
@Override
public Map<String, String> unmarshal(MapWrapper v) throws Exception {
Map<String, String> map = new HashMap<String,String>();//v.toMap();
return map;
}
@Override
public MapWrapper marshal(Map<String, String> m) throws Exception {
MapWrapper wrapper = new MapWrapper();
for(Map.Entry<String, String> entry : m.entrySet()){
wrapper.addEntry(new JAXBElement<String>(new QName(entry.getKey()), String.class, entry.getValue()));
}
return wrapper;
}
}
通过创建XML测试代码:
private static void writeAsXml(Object o, Writer writer) throws Exception
{
JAXBContext jaxb = JAXBContext.newInstance(o.getClass());
Marshaller xmlConverter = jaxb.createMarshaller();
xmlConverter.setProperty("jaxb.formatted.output", true);
xmlConverter.marshal(o, writer);
}
CustomMap map = new CustomMap();
map.addEntry("Key1","Value1");
map.addEntry("Key2","Value2");
map.addEntry("Key3","Value3");
map.addEntry("Key4","Value4");
writeAsXml(map, new PrintWriter(System.out));
并生成了XML:
<RootTag>
<Key1>Value1</Key1>
<Key2>Value2</Key2>
<Key3>Value3</Key3>
<Key4>Value4</Key4>
</RootTag>
价值1
价值2
价值3
价值4
我只需要编组,所以没有实现解编组部分 我做到了!用过的例子
从上面的帖子:创建这个类:
public class MapAdapter extends XmlAdapter<MapWrapper, Map<String, String>>{
@Override
public Map<String, String> unmarshal(MapWrapper v) throws Exception {
Map<String, String> map = new HashMap<String,String>();//v.toMap();
return map;
}
@Override
public MapWrapper marshal(Map<String, String> m) throws Exception {
MapWrapper wrapper = new MapWrapper();
for(Map.Entry<String, String> entry : m.entrySet()){
wrapper.addEntry(new JAXBElement<String>(new QName(entry.getKey()), String.class, entry.getValue()));
}
return wrapper;
}
}
通过创建XML测试代码:
private static void writeAsXml(Object o, Writer writer) throws Exception
{
JAXBContext jaxb = JAXBContext.newInstance(o.getClass());
Marshaller xmlConverter = jaxb.createMarshaller();
xmlConverter.setProperty("jaxb.formatted.output", true);
xmlConverter.marshal(o, writer);
}
CustomMap map = new CustomMap();
map.addEntry("Key1","Value1");
map.addEntry("Key2","Value2");
map.addEntry("Key3","Value3");
map.addEntry("Key4","Value4");
writeAsXml(map, new PrintWriter(System.out));
并生成了XML:
<RootTag>
<Key1>Value1</Key1>
<Key2>Value2</Key2>
<Key3>Value3</Key3>
<Key4>Value4</Key4>
</RootTag>
价值1
价值2
价值3
价值4
我只需要编组,所以没有实现解编组部分